Cambridge AS & A Level9701

Carboxylic acids (18)

Chemistry 9701 Chapter Notes

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1. The Acidity of Carboxylic Acids

Carboxylic acids are weak acids, meaning they only partially dissociate (ionise) when dissolved in water. An equilibrium is established where most of the acid molecules remain undissociated. For ethanoic acid, the equilibrium is: CH₃COOH(aq) ⇌ CH₃COO⁻(aq) + H⁺(aq). The position of this equilibrium lies far to the left. They are, however, stronger acids than alcohols. This increased acidity is due to two main factors. Firstly, the electron-withdrawing carbonyl group (C=O) pulls electron density away from the O-H bond, weakening it and making the proton (H⁺) easier to release. Secondly, the resulting carboxylate anion (e.g., CH₃COO⁻) is stabilised by resonance. The negative charge is delocalised (spread out) over the two oxygen atoms, which makes the ion more stable and less likely to re-form the acid. The acidity can be further increased by attaching electron-withdrawing groups (like chlorine) to the carbon atom next to the -COOH group. These groups pull electron density away from the carboxylate ion, spreading the negative charge even more and increasing its stability. The more electron-withdrawing groups present, the stronger the acid.

R-COOH(aq) ⇌ R-COO⁻(aq) + H⁺(aq)

Key term

Weak Acid: An acid that only partially dissociates or ionises in aqueous solution, establishing an equilibrium with its undissociated form.

Examiner insight

Examiners award marks for clearly linking the number of electron-withdrawing groups to the degree of stabilisation of the carboxylate ion and therefore the strength of the acid.

Common pitfall

Stating that electron-withdrawing groups weaken the O-H bond as the only reason for increased acidity, while forgetting to mention the crucial role of stabilising the conjugate base (carboxylate anion).

Fun fact

Trichloroethanoic acid (TCA) is strong enough to be used in cosmetics for chemical peels and tattoo removal, as it causes the top layers of skin to shed.

Worked example 14 marks

Arrange the following acids in order of increasing strength (weakest first): ethanoic acid, trichloroethanoic acid, chloroethanoic acid. Justify your answer.

  1. 1

    Step 1: Identify the structures. Ethanoic acid (CH₃COOH), Chloroethanoic acid (CH₂ClCOOH), Trichloroethanoic acid (CCl₃COOH).

  2. 2

    Step 2: State the order. The order of increasing acid strength is: ethanoic acid < chloroethanoic acid < trichloroethanoic acid.

  3. 3

    Step 3: Explain the effect of chlorine. Chlorine is an electron-withdrawing atom. It pulls electron density away from the -COOH group through the carbon chain (the inductive effect).

  4. 4

    Step 4: Link this effect to the conjugate base. This withdrawal of electron density helps to stabilise the negative charge on the carboxylate anion (R-COO⁻) that forms upon dissociation.

  5. 5

    Step 5: Relate stability to acid strength. A more stable conjugate base means the acid is more likely to dissociate, making it a stronger acid. Trichloroethanoic acid has three Cl atoms, so its conjugate base is the most stabilised, making it the strongest acid of the three.

Recap

  • Carboxylic acids are weak acids because they only partially dissociate in water.
  • The carboxylate anion is stabilised by delocalisation of the negative charge across the O-C-O system.
  • Electron-withdrawing groups (like Cl) attached to the carbon chain increase acid strength.
  • The more electron-withdrawing groups, the stronger the carboxylic acid becomes.
  • Increased acid strength is due to the increased stability of the resulting carboxylate anion.

Quick check

  1. Explain in one sentence why ethanoic acid is a stronger acid than ethanol.1 mark
  2. Which is a stronger acid, CH₂FCOOH or CH₂ICOOH? Why?2 marks

2. Formation of Carboxylic Acids

There are two principal laboratory methods for preparing carboxylic acids. The first is the oxidation of primary alcohols or aldehydes. This is achieved by heating the primary alcohol or aldehyde with an excess of a strong oxidising agent, typically acidified potassium dichromate(VI) (K₂Cr₂O₇/H₂SO₄), under reflux. Refluxing ensures that any volatile intermediates (like the aldehyde) do not escape and are fully oxidised to the carboxylic acid. The colour change from orange (Cr₂O₇²⁻) to green (Cr³⁺) indicates the reaction has occurred. The second method is the hydrolysis of nitriles (R-C≡N). This involves refluxing the nitrile with a dilute acid (e.g., HCl(aq)) or alkali (e.g., NaOH(aq)). Acid hydrolysis produces the carboxylic acid and an ammonium salt (e.g., NH₄Cl), while alkaline hydrolysis produces the sodium salt of the carboxylic acid, which must then be acidified to form the carboxylic acid itself. This nitrile route is useful as it increases the length of the carbon chain by one carbon atom.

Primary Alcohol Oxidation: RCH₂OH + 2[O] → RCOOH + H₂O

Aldehyde Oxidation: RCHO + [O] → RCOOH

Nitrile Hydrolysis (Acid): RCN + 2H₂O + H⁺ → RCOOH + NH₄⁺

Key term

Reflux: The process of heating a reaction mixture in a vessel with an attached condenser, which cools and condenses vapours back into the vessel, allowing for prolonged heating without loss of volatile substances.

Common pitfall

Forgetting that hydrolysis of a nitrile adds a carbon atom to the chain. For example, hydrolysing ethanenitrile (CH₃CN) gives ethanoic acid (CH₃COOH), not methanoic acid.

Worked example 15 marks

A student wants to prepare propanoic acid, CH₃CH₂COOH, starting from a two-carbon compound. Describe the two-step synthesis, including reagents, conditions, and equations.

  1. 1

    Step 1: Identify the starting material. To increase the carbon chain from two to three carbons, a nitrile must be formed. The starting material will be a two-carbon halogenoalkane, such as bromoethane (CH₃CH₂Br).

  2. 2

    Step 2: Reaction 1 - Formation of the nitrile. React bromoethane with potassium cyanide (KCN) in ethanol under reflux. This is a nucleophilic substitution reaction. Equation: CH₃CH₂Br + KCN → CH₃CH₂CN + KBr. The product is propanenitrile.

  3. 3

    Step 3: Reaction 2 - Hydrolysis of the nitrile. Hydrolyse the propanenitrile by refluxing with dilute hydrochloric acid. Equation: CH₃CH₂CN + 2H₂O + HCl → CH₃CH₂COOH + NH₄Cl.

  4. 4

    Step 4: Summarise reagents and conditions. Step 1: KCN in ethanol, reflux. Step 2: Dilute HCl, reflux.

Recap

  • Carboxylic acids are formed by oxidising primary alcohols or aldehydes.
  • The oxidation requires a strong oxidising agent (e.g., acidified K₂Cr₂O₇) and reflux conditions.
  • Carboxylic acids can also be formed by the acid or alkaline hydrolysis of nitriles.
  • The nitrile hydrolysis route increases the carbon chain length by one carbon atom.

Quick check

  1. What colour change is observed when propan-1-ol is refluxed with acidified potassium dichromate(VI)?1 mark
  2. What are the two products of the acid hydrolysis of ethanenitrile?2 marks

3. Making Acyl Chlorides

Acyl chlorides (RCOCl) are highly reactive derivatives of carboxylic acids, making them useful intermediates in synthesis. They are formed by replacing the hydroxyl (-OH) group of a carboxylic acid with a chlorine atom. This is a substitution reaction. There are three common chlorinating agents used in the lab:

  1. Thionyl chloride (SOCl₂): This is often the best choice. The reaction produces the acyl chloride, sulfur dioxide gas, and hydrogen chloride gas. Since the by-products are gaseous, they escape from the reaction mixture, leaving a relatively pure acyl chloride, which simplifies purification.
  2. Phosphorus(V) chloride (PCl₅): This reacts vigorously at room temperature to produce the acyl chloride, phosphoryl chloride (POCl₃), and hydrogen chloride gas. The by-products can be difficult to separate from the desired product.
  3. Phosphorus(III) chloride (PCl₃): This reaction requires heating. It produces the acyl chloride and phosphorous acid (H₃PO₃). The equation requires balancing with a 3:1 ratio of carboxylic acid to PCl₃.

RCOOH + SOCl₂ → RCOCl + SO₂(g) + HCl(g)

RCOOH + PCl₅ → RCOCl + POCl₃ + HCl(g)

3RCOOH + PCl₃ → 3RCOCl + H₃PO₃

Key term

Acyl Chloride: A reactive organic compound containing the -COCl functional group, derived from a carboxylic acid by replacement of the -OH group with a -Cl atom.

Examiner insight

Marks are frequently awarded for correctly identifying the by-products of each chlorinating agent, especially for explaining why the gaseous by-products of the SOCl₂ reaction make it a superior method for synthesis.

Fun fact

The reaction of a carboxylic acid with PCl₅ producing misty fumes of HCl is a classic chemical test for the carboxylic acid functional group.

Worked example 13 marks

Write a balanced chemical equation for the formation of propanoyl chloride from propanoic acid using thionyl chloride. State one reason why this is the preferred method.

  1. 1

    Step 1: Write the formula for propanoic acid (CH₃CH₂COOH) and propanoyl chloride (CH₃CH₂COCl).

  2. 2

    Step 2: Write the full equation using SOCl₂ as the reagent. CH₃CH₂COOH + SOCl₂ → CH₃CH₂COCl + SO₂ + HCl.

  3. 3

    Step 3: State the advantage. This method is preferred because the other two products, sulfur dioxide (SO₂) and hydrogen chloride (HCl), are both gases.

  4. 4

    Step 4: Explain the benefit. As gases, they escape from the reaction mixture, leaving a purer sample of the liquid acyl chloride, which makes separation and purification much easier.

Recap

  • Acyl chlorides are formed by substituting the -OH of a carboxylic acid with -Cl.
  • Common chlorinating agents are SOCl₂, PCl₅, and PCl₃.
  • The reaction with thionyl chloride (SOCl₂) is often preferred.
  • The by-products of the SOCl₂ reaction are SO₂(g) and HCl(g), which are easily removed.

Quick check

  1. Name the phosphorus-containing product when ethanoic acid reacts with PCl₅.1 mark

4. Reactions of Acyl Chlorides

Acyl chlorides are powerful acylating agents, meaning they are excellent at transferring their acyl group (R-C=O) to other molecules. Their high reactivity stems from the highly electron-deficient (δ+) carbonyl carbon, which is attacked by nucleophiles. These reactions are vigorous and proceed via a nucleophilic addition-elimination mechanism. Key reactions include:

  1. Hydrolysis (with water): A violent reaction occurs with cold water, producing the corresponding carboxylic acid and steamy/misty fumes of hydrogen chloride gas. Example: CH₃COCl + H₂O → CH₃COOH + HCl.
  2. Reaction with Alcohols: A vigorous reaction produces an ester and HCl. This is a much faster and more efficient way to make esters than traditional acid-catalysed esterification, and the reaction goes to completion. Example: CH₃COCl + CH₃CH₂OH → CH₃COOCH₂CH₃ + HCl.
  3. Reaction with Phenols: Similar to alcohols, acyl chlorides react with phenols to form phenolic esters. This reaction is important because phenols do not readily form esters with carboxylic acids directly. Example: C₆H₅OH + CH₃COCl → CH₃COOC₆H₅ + HCl.
  4. Reaction with Ammonia and Amines: A violent reaction occurs with ammonia to form a primary amide. With a primary amine, an N-substituted amide is formed. In both cases, two moles of ammonia/amine are required per mole of acyl chloride: one acts as the nucleophile, and the second acts as a base to mop up the HCl produced, forming an ammonium salt. Example: CH₃COCl + 2NH₃ → CH₃CONH₂ + NH₄Cl.

Hydrolysis: RCOCl + H₂O → RCOOH + HCl

With Alcohol: RCOCl + R'OH → RCOOR' + HCl

With Phenol: RCOCl + C₆H₅OH → RCOOC₆H₅ + HCl

With Amine: RCOCl + 2R'NH₂ → RCONHR' + R'NH₃⁺Cl⁻

Key term

Nucleophilic Addition-Elimination: A two-step reaction mechanism where a nucleophile adds to a polar double bond (addition) followed by the removal of a leaving group (elimination).

Common pitfall

Forgetting the second mole of amine/ammonia in the reaction equation and writing HCl as a product instead of the ammonium salt (e.g., RNH₃⁺Cl⁻).

Worked example 16 marks

Ethanoyl chloride is reacted separately with(a) water,(b) ethanol, and(c) methylamine. For each reaction, name the organic product and write a balanced equation.

  1. 1

    Part(a) Water: The organic product is a carboxylic acid, ethanoic acid. Equation: CH₃COCl + H₂O → CH₃COOH + HCl.

  2. 2

    Part(b) Ethanol: The organic product is an ester, ethyl ethanoate. Equation: CH₃COCl + CH₃CH₂OH → CH₃COOCH₂CH₃ + HCl.

  3. 3

    Part(c) Methylamine: The organic product is an N-substituted amide, N-methylethanamide. Two equivalents of the amine are used. Equation: CH₃COCl + 2CH₃NH₂ → CH₃CONHCH₃ + CH₃NH₃⁺Cl⁻.

Recap

  • Acyl chlorides react readily with nucleophiles like water, alcohols, phenols, and amines.
  • Reaction with water forms a carboxylic acid and HCl fumes.
  • Reaction with an alcohol or phenol forms an ester.
  • Reaction with ammonia or a primary amine forms an amide.
  • Reactions with amines require two molar equivalents of the amine.

Quick check

  1. What functional group is formed when propanoyl chloride reacts with phenol?1 mark
  2. Why are two moles of ammonia needed for every one mole of acyl chloride in the formation of an amide?1 mark

5. Hydrolysis Reactivity and Mechanism

The ease with which a chlorine-containing compound is hydrolysed by water depends greatly on its structure. The order of reactivity is: Acyl Chloride > Halogenoalkane > Halogenoarene.

  • Acyl Chlorides (e.g., CH₃COCl): Hydrolyse extremely rapidly, even with cold water. The carbonyl carbon is very electron-deficient (highly δ+) because it is bonded to two highly electronegative atoms (O and Cl). This makes it very susceptible to attack by a nucleophile like water.
  • Halogenoalkanes (e.g., CH₃CH₂Cl): Hydrolyse much more slowly, typically requiring heating with aqueous alkali (a stronger nucleophile than water). The carbon bonded to the chlorine is δ+, but less so than in an acyl chloride as it's only attached to one electronegative atom.
  • Halogenoarenes (e.g., Chlorobenzene, C₆H₅Cl): Are extremely resistant to hydrolysis and require very harsh conditions (e.g., high temperature and pressure with NaOH). This is because a lone pair of electrons from the chlorine atom is delocalised into the benzene ring's π-system. This gives the C-Cl bond partial double bond character, making it much stronger and harder to break.

The mechanism for acyl chloride hydrolysis is nucleophilic addition-elimination. In step 1 (addition), a water molecule attacks the δ+ carbonyl carbon. In step 2 (elimination), the C=O bond reforms, and the chloride ion is expelled as a good leaving group.

Key term

Delocalisation: The phenomenon where electrons are shared among more than two atoms in a molecule or ion, resulting in increased stability.

Examiner insight

For mechanism questions, examiners require precise curly arrows that start from a lone pair or a bond and point clearly to the atom where the new bond is forming or to the atom receiving the electron pair.

Fun fact

The unreactivity of the C-Cl bond in aryl chlorides is a key reason why compounds like DDT and PCBs were so persistent in the environment, leading to their ban.

Worked example 14 marks

Draw the mechanism for the hydrolysis of ethanoyl chloride (CH₃COCl) by water. Use curly arrows to show the movement of electron pairs.

  1. 1

    Step 1: Draw the reactants, ethanoyl chloride and a water molecule. Show the δ+ on the carbonyl carbon and the δ- on the carbonyl oxygen. Show the lone pair on the water's oxygen atom.

  2. 2

    Step 2 (Addition): Draw a curly arrow from the lone pair of the water's oxygen atom to the δ+ carbonyl carbon of the ethanoyl chloride. Draw another curly arrow from the C=O double bond up to the oxygen atom. This forms a tetrahedral intermediate.

  3. 3

    Step 3: Draw the tetrahedral intermediate. It has a C-O single bond (with a negative charge on the O), a C-Cl bond, a C-CH₃ bond, and a bond to the water molecule, which now has a positive charge on its oxygen (O-H₂⁺).

  4. 4

    Step 4 (Elimination): Draw a curly arrow from the lone pair on the negatively charged oxygen down to reform the C=O double bond. Simultaneously, draw a curly arrow from the C-Cl bond onto the chlorine atom, showing it leaving as a Cl⁻ ion.

  5. 5

    Step 5 (Deprotonation): The intermediate is now CH₃C=O⁺H₂. The Cl⁻ ion (or another water molecule) acts as a base. Draw a curly arrow from the H-O bond of the attached water group onto the positive oxygen atom. This releases H⁺, which combines with the Cl⁻ to form HCl, leaving the final product, ethanoic acid (CH₃COOH).

Worked example 24 marks

Explain why chlorobenzene is much less reactive towards hydrolysis than ethanoyl chloride.

  1. 1

    Step 1: State the reactivity of ethanoyl chloride. Ethanoyl chloride is very reactive because the carbonyl carbon is highly electron deficient (δ+) due to the electron-withdrawing effect of both the oxygen and chlorine atoms, making it susceptible to nucleophilic attack.

  2. 2

    Step 2: State the reactivity of chlorobenzene. Chlorobenzene is unreactive towards hydrolysis.

  3. 3

    Step 3: Explain the unreactivity of chlorobenzene. A lone pair of electrons from the chlorine atom's p-orbital overlaps with the delocalised π-system of the benzene ring.

  4. 4

    Step 4: Describe the consequences. This delocalisation gives the C-Cl bond partial double bond character, making it stronger and harder to break. It also reduces the electron deficiency of the carbon atom attached to the chlorine, making it less susceptible to nucleophilic attack.

Recap

  • The order of hydrolysis reactivity is: Acyl Chloride >> Halogenoalkane > Halogenoarene.
  • Acyl chlorides are highly reactive due to the very electron-deficient carbonyl carbon.
  • Halogenoarenes are unreactive due to delocalisation of chlorine's lone pair into the benzene ring.
  • This delocalisation gives the C-Cl bond partial double bond character, strengthening it.
  • Acyl chloride hydrolysis proceeds via a two-step nucleophilic addition-elimination mechanism.

Quick check

  1. What is the name of the mechanism for the hydrolysis of an acyl chloride?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Name the organic product formed when propanoic acid is reduced by LiAlH₄ in dry ether.1 mark
  2. Write a balanced equation for the reaction of ethanoic acid with solid sodium carbonate.2 marks
  3. Explain, with reference to the stability of the ions formed, why dichloroethanoic acid is a stronger acid than chloroethanoic acid.3 marks
  4. Butanoyl chloride is added to a beaker of cold water. Describe two observations and write an equation for the reaction.3 marks
  5. Ethanol can be converted into ethanoic acid in a single step. State the reagent(s) and condition(s) required for this conversion.2 marks
  6. Draw the skeletal formula of the organic product formed when propanoyl chloride reacts with an excess of ethylamine (CH₃CH₂NH₂).2 marks
  7. A compound X has the molecular formula C₄H₇OCl. X reacts vigorously with water to form compound Y, C₄H₈O₂, and misty fumes. When X reacts with ethanol, it forms compound Z, C₆H₁₂O₂. Deduce the displayed formulae of X, Y and Z.3 marks
  8. Compare and explain the rates of reaction of ethanoyl chloride and chloroethane with aqueous sodium hydroxide. In your answer, you should refer to the atoms and bonds involved.4 marks
  9. Draw the full mechanism for the reaction between ethanoyl chloride and ammonia (NH₃) to form ethanamide. Use curly arrows to represent the movement of electron pairs.4 marks
  10. Methanoic acid (HCOOH) can be distinguished from ethanoic acid (CH₃COOH) by warming with a suitable chemical reagent. Name a suitable reagent, state the observation with methanoic acid, and explain why ethanoic acid gives no reaction.3 marks

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