Cambridge AS & A Level9701

Periodicity of physical properties of the elements in Period 3

Chemistry 9701 Chapter Notes

What this chapter covers

Periodicity of physical properties of the elements in Period 3Periodicity of chemical properties of the elements in Period 3Chemical periodicity of other elements
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1. Atomic and Ionic Radii Across Period 3

Periodicity is the repeating pattern of properties of elements across different periods. As you move from left to right across Period 3 (Na to Ar), the physical properties change in a predictable way. Atomic radius is the first key trend. It consistently decreases across the period. This is because, from sodium to argon, a proton is added to the nucleus and an electron is added to the same outer shell (the third shell). The increasing nuclear charge pulls the electrons in this outer shell more strongly towards the nucleus, shrinking the atom. The shielding effect from the inner shells remains relatively constant, so it doesn't counteract the stronger pull. Ionic radius also shows clear trends. Metal atoms (Na, Mg, Al) lose their outer shell electrons to form positive ions (cations). These cations are much smaller than their parent atoms because they have lost an entire electron shell and the remaining electrons are pulled more tightly by the unchanged nuclear charge. Non-metal atoms (P, S, Cl) gain electrons to form negative ions (anions). These anions are larger than their parent atoms because the addition of electrons increases the repulsion between the electrons in the outer shell, causing it to expand.

Key term

Nuclear Charge: The total positive charge of the protons in the nucleus of an atom, which increases by one for each successive element in a period.

Examiner insight

Examiners expect you to clearly link the increasing nuclear charge to a stronger electrostatic attraction for the valence electrons, which are in the same principal shell.

Common pitfall

Stating that shielding increases across a period. Shielding from inner shells is relatively constant as electrons are added to the same outer shell.

Worked example 13 marks

Explain why the atomic radius of chlorine is smaller than that of sodium.

  1. 1

    Step 1: Identify the positions of Na and Cl. Both are in Period 3. Sodium is in Group 1 and Chlorine is in Group 17.

  2. 2

    Step 2: Compare their nuclear charge. Chlorine has 17 protons in its nucleus, while sodium has 11 protons. Therefore, chlorine has a greater nuclear charge.

  3. 3

    Step 3: Compare their electron arrangement. In both atoms, the outermost electrons are in the 3rd principal energy shell.

  4. 4

    Step 4: Relate nuclear charge and shielding to atomic radius. The increased nuclear charge in chlorine attracts the electrons in the 3rd shell more strongly than in sodium. The shielding from inner shell electrons is similar for both. This stronger attraction pulls the electron cloud closer to the nucleus, resulting in a smaller atomic radius for chlorine.

Worked example 23 marks

Explain why a magnesium ion (Mg²⁺) is significantly smaller than a magnesium atom (Mg).

  1. 1

    Step 1: Compare the number of protons and electrons. A Mg atom has 12 protons and 12 electrons (2.8.2). A Mg²⁺ ion has 12 protons and 10 electrons (2.8).

  2. 2

    Step 2: Identify the change in electron shells. The Mg atom has electrons in 3 shells, while the Mg²⁺ ion has electrons in only 2 shells. The entire outer shell has been removed.

  3. 3

    Step 3: Compare the electrostatic attraction. The 12 protons in the Mg²⁺ ion are now attracting only 10 electrons, leading to a much stronger effective pull on each remaining electron compared to the neutral atom. This pulls the remaining electron shells closer to the nucleus.

  4. 4

    Step 4: Conclude. The combination of losing the outermost shell and the increased attraction on the remaining electrons makes the Mg²⁺ ion much smaller than the Mg atom.

Recap

  • Atomic radius decreases across Period 3.
  • This is due to increasing nuclear charge attracting electrons in the same outer shell more strongly.
  • Shielding effect from inner shells is relatively constant across the period.
  • Positive ions (cations) are much smaller than their parent atoms.
  • Negative ions (anions) are larger than their parent atoms.

Quick check

  1. Which particle is larger: a sulfur atom (S) or a sulfide ion (S²⁻)?1 mark
  2. Arrange Na⁺, Mg²⁺, and Al³⁺ in order of increasing ionic radius.1 mark

3. Structure, Melting Point, and Conductivity

The structure and bonding of the elements across Period 3 change dramatically, which directly explains the trends in their melting points and electrical conductivity.

  • Sodium (Na), Magnesium (Mg), and Aluminium (Al): These are metals with giant metallic lattice structures. They are held together by strong metallic bonds, which is the electrostatic attraction between positive metal ions and a 'sea' of delocalised electrons. From Na to Mg to Al, the number of delocalised electrons per atom increases (1, 2, 3 respectively) and the ionic charge increases (+1, +2, +3). This leads to a stronger metallic bond, so the melting point increases. These delocalised electrons are mobile charge carriers, so all three are good electrical conductors, with conductivity increasing from Na to Al.
  • Silicon (Si): This is a metalloid with a giant molecular (or giant covalent) structure, similar to diamond. Each Si atom is covalently bonded to four others in a tetrahedral arrangement. To melt silicon, these numerous strong covalent bonds must be broken, which requires a vast amount of energy. This gives silicon a very high melting point, the highest in the period. It has very few free electrons, making it a semiconductor.
  • Phosphorus (P), Sulfur (S), and Chlorine (Cl): These are non-metals with simple molecular structures. They exist as small, discrete molecules (P₄, S₈, Cl₂). The covalent bonds within the molecules are strong, but the forces between the molecules are weak van der Waals' forces. Melting only requires overcoming these weak intermolecular forces, not breaking the covalent bonds. Therefore, they have low melting points. The melting point increases from Cl₂ to P₄ to S₈ because the size of the molecule and number of electrons increases, leading to stronger van der Waals' forces. As there are no mobile charge carriers, they are electrical insulators.
  • Argon (Ar): This is a noble gas that exists as individual atoms (monatomic). The only forces between the atoms are extremely weak van der Waals' forces, so it has a very low melting point.

Key term

Metallic Bonding: The electrostatic attraction between a lattice of positive metal ions and a surrounding 'sea' of delocalised electrons.

Examiner insight

For questions on melting points, you must explicitly state what is being broken or overcome: strong metallic bonds, strong covalent bonds, or weak intermolecular forces.

Common pitfall

Confusing the breaking of strong covalent bonds within molecules with the overcoming of weak intermolecular forces between molecules when explaining the low melting points of P, S, and Cl.

Worked example 14 marks

Explain why silicon has a very high melting point, whereas phosphorus has a low melting point.

  1. 1

    Step 1: Describe the structure and bonding in silicon. Silicon has a giant molecular (or covalent) structure. Each silicon atom is joined to four other silicon atoms by strong covalent bonds.

  2. 2

    Step 2: Relate structure to melting point for silicon. A large amount of energy is needed to break these numerous strong covalent bonds, resulting in a very high melting point.

  3. 3

    Step 3: Describe the structure and bonding in phosphorus. Phosphorus has a simple molecular structure, existing as P₄ molecules. The covalent bonds within the P₄ molecules are strong.

  4. 4

    Step 4: Relate structure to melting point for phosphorus. However, between the P₄ molecules, there are only weak van der Waals' forces. Little energy is needed to overcome these weak intermolecular forces, resulting in a low melting point.

Worked example 23 marks

Explain why aluminium is a better electrical conductor than sodium.

  1. 1

    Step 1: Identify the bonding in both elements. Both aluminium and sodium have metallic bonding, with a lattice of positive ions and delocalised electrons.

  2. 2

    Step 2: State how electrical conductivity occurs. Conductivity in metals is due to the movement of these delocalised electrons.

  3. 3

    Step 3: Compare the number of delocalised electrons. Each aluminium atom contributes three delocalised electrons to the 'sea' of electrons, whereas each sodium atom contributes only one.

  4. 4

    Step 4: Conclude. Since aluminium has a greater number of mobile charge carriers (delocalised electrons) per unit volume, it is a better electrical conductor than sodium.

Recap

  • Melting points peak at silicon (giant covalent) and are lowest for the simple molecular elements.
  • Na, Mg, and Al have giant metallic structures, and their melting points increase across the period.
  • P, S, and Cl have simple molecular structures, and their melting points are low.
  • Electrical conductivity is high for the metals (Na, Mg, Al) and virtually zero for the non-metals (P, S, Cl, Ar).
  • Silicon is a semiconductor, with conductivity between that of metals and non-metals.

Quick check

  1. What type of structure does magnesium have?1 mark
  2. Why is sulfur's melting point (as S₈) higher than chlorine's (as Cl₂)?2 marks

4. Period 3 Oxides: Bonding and Acidity

The properties of Period 3 oxides transition from basic to amphoteric to acidic across the period, which is explained by the change in bonding from ionic to covalent.

  • Na₂O and MgO: These are basic oxides. They have giant ionic lattice structures due to the large electronegativity difference between the metal and oxygen. This results in high melting points. They react with water to form alkaline solutions (e.g., Na₂O + H₂O → 2NaOH) and react with acids to form a salt and water (e.g., MgO + 2HCl → MgCl₂ + H₂O).
  • Al₂O₃: This is an amphoteric oxide, meaning it can act as both an acid and a base. It has a giant ionic lattice with significant covalent character. It is insoluble in water but reacts with both strong acids and strong bases. Reaction with acid: Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O. Reaction with base: Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄].
  • SiO₂: This is an acidic oxide with a giant covalent structure. It has a very high melting point. It is insoluble in water but will react with strong bases like hot, concentrated sodium hydroxide: SiO₂ + 2NaOH → Na₂SiO₃ + H₂O.
  • P₄O₁₀ and SO₂/SO₃: These are acidic oxides. They have simple molecular structures, resulting in low melting and boiling points. They react vigorously with water to form strong acids. P₄O₁₀ + 6H₂O → 4H₃PO₄ (phosphoric acid). SO₃ + H₂O → H₂SO₄ (sulfuric acid).

Na₂O(s) + H₂O(l) → 2NaOH(aq)

MgO(s) + 2HCl(aq) → MgCl₂(aq) + H₂O(l)

Al₂O₃(s) + 6H⁺(aq) → 2Al³⁺(aq) + 3H₂O(l)

Al₂O₃(s) + 2OH⁻(aq) + 3H₂O(l) → 2[Al(OH)₄]⁻(aq)

P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq)

SO₃(g) + H₂O(l) → H₂SO₄(aq)

Key term

Amphoteric: A substance, such as aluminium oxide, that can exhibit both acidic and basic properties.

Examiner insight

Be precise with the acid/base terminology. Na₂O is basic, SiO₂ is acidic, and Al₂O₃ is amphoteric. Simply stating they react is not enough.

Common pitfall

Writing an incorrect formula for the product of the reaction between Al₂O₃ and NaOH. The complex ion is tetrahydroxoaluminate(III), [Al(OH)₄]⁻.

Fun fact

The amphoteric nature of aluminium oxide is why aluminium cookware can be damaged by both very acidic foods (like tomatoes) and very alkaline cleaning agents.

Worked example 13 marks

Write an equation for the reaction of aluminium oxide withi) sulfuric acid and ii) hot, concentrated sodium hydroxide solution. What property of aluminium oxide do these reactions demonstrate?

  1. 1

    Step 1: Write the equation for the reaction with acid. Aluminium oxide is a base here. Al₂O₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂O.

  2. 2

    Step 2: Write the equation for the reaction with base. Aluminium oxide is an acid here. Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄].

  3. 3

    Step 3: State the property. Since aluminium oxide reacts with both an acid and a base, it is demonstrating amphoteric properties.

Recap

  • Oxide acidity increases across Period 3: Basic → Amphoteric → Acidic.
  • Na₂O and MgO are basic and form giant ionic lattices.
  • Al₂O₃ is amphoteric.
  • SiO₂ is acidic and has a giant covalent structure.
  • P₄O₁₀ and SOₓ are acidic and have simple molecular structures.
  • The change in properties is due to the bonding changing from ionic to covalent.

Quick check

  1. What is the acid/base character of magnesium oxide?1 mark
  2. Which Period 3 oxide has a giant covalent structure?1 mark

5. Period 3 Chlorides: Bonding and Hydrolysis

The trend in bonding for Period 3 chlorides mirrors that of the oxides, changing from ionic to covalent. This directly impacts their melting points and, most importantly, their reaction with water.

  • NaCl and MgCl₂: These are white crystalline solids with giant ionic lattice structures and high melting points. They do not react with water but simply dissolve to form hydrated ions. The resulting solutions are approximately neutral (NaCl gives pH 7, MgCl₂ gives pH ~6.5 due to slight polarisation of water by the Mg²⁺ ion).
  • AlCl₃: This is a complex case. As a solid, it has an ionic lattice. However, it has significant covalent character and sublimes at 180°C, forming a dimer, Al₂Cl₆, which is a simple molecule. It reacts vigorously and exothermically with water in a reaction called hydrolysis. White, steamy fumes of hydrogen chloride gas are produced, and the remaining solution is strongly acidic (pH ~3). A simplified equation is AlCl₃(s) + 3H₂O(l) → Al(OH)₃(s) + 3HCl(g).
  • SiCl₄ and PCl₅: These are covalent substances that are liquids or low melting point solids at room temperature. They have simple molecular structures. They are rapidly and violently hydrolysed by water, producing dense white fumes of HCl and an acidic solution. SiCl₄(l) + 2H₂O(l) → SiO₂(s) + 4HCl(g). PCl₅(s) + 4H₂O(l) → H₃PO₄(aq) + 5HCl(g).
  • The trend is clear: ionic chlorides dissolve, while covalent chlorides are hydrolysed by water.

NaCl(s) + aq → Na⁺(aq) + Cl⁻(aq)

AlCl₃(s) + 3H₂O(l) → Al(OH)₃(s) + 3HCl(g)

SiCl₄(l) + 2H₂O(l) → SiO₂(s) + 4HCl(g)

PCl₅(s) + 4H₂O(l) → H₃PO₄(aq) + 5HCl(g)

Key term

Hydrolysis: A chemical reaction in which a compound is broken down by reaction with water, often resulting in an acidic or alkaline solution.

Examiner insight

Examiners look for the key observation of 'white fumes' or 'steamy fumes' of HCl gas when describing the hydrolysis of covalent chlorides like SiCl₄ or PCl₅.

Common pitfall

Stating that NaCl and MgCl₂ are hydrolysed by water. They only dissolve; the ions become hydrated. Significant hydrolysis only begins with AlCl₃.

Worked example 15 marks

Compare and contrast the reaction, if any, of sodium chloride and silicon tetrachloride with water. For each, state the observations, the approximate pH of the final solution, and write a relevant equation.

  1. 1

    Step 1: Describe the reaction for sodium chloride. Sodium chloride does not react with water, it dissolves. There are no visible fumes. The equation is NaCl(s) + aq → Na⁺(aq) + Cl⁻(aq). The final pH is 7.

  2. 2

    Step 2: Describe the reaction for silicon tetrachloride. Silicon tetrachloride reacts violently with water (hydrolysis). Dense white/steamy fumes of hydrogen chloride are observed, and a white precipitate of silicon dioxide may form.

  3. 3

    Step 3: Write the equation and state the pH for the SiCl₄ reaction. The equation is SiCl₄(l) + 2H₂O(l) → SiO₂(s) + 4HCl(aq/g). Due to the formation of hydrochloric acid, the resulting solution is strongly acidic, with a pH of around 1-2.

Recap

  • Bonding in chlorides changes from ionic (NaCl, MgCl₂) to covalent (AlCl₃, SiCl₄, PCl₅) across Period 3.
  • Ionic chlorides dissolve in water to give neutral or very weakly acidic solutions.
  • Covalent chlorides are hydrolysed by water, producing steamy fumes of HCl and an acidic solution.
  • The vigour of hydrolysis increases from AlCl₃ to PCl₅.
  • Melting points decrease dramatically after MgCl₂ as the structure changes from giant ionic to simple molecular.

Quick check

  1. What is observed when water is added to a sample of phosphorus(V) chloride?2 marks
  2. What is the approximate pH of a solution of magnesium chloride in water?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Define the term 'first ionisation energy' and write a general equation to represent it.2 marks
  2. Place sodium, silicon, and sulfur in order of increasing melting point and briefly justify your order by referring to their structure and bonding.4 marks
  3. Explain why the atomic radius decreases from sodium to chlorine across Period 3.3 marks
  4. Explain fully why magnesium has a higher first ionisation energy than aluminium.3 marks
  5. Describe the bonding and structure in sodium oxide and silicon dioxide. Use these descriptions to explain the difference in their melting points.4 marks
  6. Write balanced chemical equations, including state symbols, for the reaction of phosphorus(V) oxide with water and for the reaction of sodium oxide with water.2 marks
  7. An element in Period 3 has a very high melting point and is a semiconductor. Its oxide is acidic. Identify the element and write an equation for the reaction of its oxide with hot, concentrated sodium hydroxide.3 marks
  8. Compare the reactions of magnesium chloride and phosphorus(V) chloride with water. For each reaction, state the observations, the approximate pH of the resulting solution, and write a balanced chemical equation.6 marks
  9. Explain why sulfur (S₈) has a higher melting point than phosphorus (P₄), and why both have low melting points compared to silicon.4 marks
  10. The graph of first ionisation energy against atomic number for Period 3 shows a general increase but with two anomalies. Identify the elements that cause these anomalies and explain the electronic reasons for both.5 marks

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