Cambridge AS & A Level9701

Physical properties of the Group 17 elements

Chemistry 9701 Chapter Notes

What this chapter covers

Physical properties of the Group 17 elementsThe chemical properties of the halogen elements and the hydrogen halidesSome reactions of the halide ionsThe reactions of chlorine
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1. Meet the Halogens: Group 17

The elements in Group 17 of the Periodic Table are known as the halogens. This family includes fluorine (F), chlorine (Cl), bromine (Br), and iodine (I). The defining characteristic of a halogen atom is that it has seven electrons in its outermost shell. To achieve a stable electron arrangement like a noble gas (an octet), they are highly reactive and tend to gain one electron. At room temperature and pressure, they exist not as single atoms but as diatomic molecules, written as F₂, Cl₂, Br₂, and I₂. Within each molecule, the two atoms are joined by a single covalent bond, where they share a pair of electrons.

General electronic configuration: ns²np⁵

Diatomic molecule: X₂ (where X = F, Cl, Br, I)

Key term

Diatomic Molecule: A molecule containing exactly two atoms that are chemically bonded together.

Fun fact

The name 'halogen' comes from the Greek words 'hals' (salt) and 'gen' (to produce), because they readily react with metals to form salts, such as sodium chloride (NaCl).

Worked example 13 marks

The atomic number of a bromine atom is 35. Write its electronic configuration and explain why it forms a Br₂ molecule.

  1. 1

    Step 1: Determine the number of electrons. A neutral bromine atom has 35 electrons.

  2. 2

    Step 2: Write the electronic configuration by filling orbitals in order. The configuration is 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁵.

  3. 3

    Step 3: Identify the outer shell electrons. Bromine has 7 electrons in its outer shell (the 4th shell).

  4. 4

    Step 4: Explain molecule formation. To achieve a stable octet (8 outer electrons), two bromine atoms each share one of their outer electrons. This forms a single covalent bond between them, resulting in a stable Br₂ molecule.

Recap

  • Group 17 elements are called the halogens.
  • Halogen atoms possess seven electrons in their outer shell.
  • Under standard conditions, halogens exist as diatomic molecules (X₂).
  • The two atoms in a halogen molecule are joined by a single covalent bond.

Quick check

  1. How many electrons does a fluorine atom need to gain to have a full outer shell?1 mark

3. Appearance, State and Atomic Radius

The physical properties of halogens show clear trends down the group. At room temperature (approx. 20°C), their physical states change: fluorine and chlorine are gases, bromine is a volatile liquid, and iodine is a solid. The colour of the halogens also deepens down the group: fluorine is a pale-yellow gas, chlorine is a greenish-yellow gas, bromine is a red-brown liquid, and iodine is a grey-black solid which produces a violet vapour when heated (sublimation). Another important trend is atomic radius, which increases down the group. This is because each element down the group has one more principal electron shell than the one above it. Although the nuclear charge (number of protons) increases, the outer electrons are further from the nucleus and experience greater shielding from the attraction of the nucleus by the inner shells of electrons. This effect of adding a new shell is the dominant factor, causing the atom to be larger.

Key term

Electron Shielding: The repulsion between inner-shell electrons and outer-shell electrons which reduces the net electrostatic attraction between the positive nucleus and the outer electrons.

Examiner insight

A complete answer for the trend in atomic radius must mention that outer electrons are in a higher energy level (further from the nucleus) and that there is increased shielding.

Common pitfall

Forgetting to mention both the increasing number of shells AND the effect of shielding when explaining the trend in atomic radius.

Worked example 14 marks

a) Describe the physical state and colour of chlorine and iodine at room temperature. [2]b) Explain why an iodine atom is larger than a chlorine atom. [2]

  1. 1

    a) Chlorine is a greenish-yellow gas at room temperature. Iodine is a grey-black solid at room temperature.

  2. 2

    b) Step 1: Both iodine and chlorine are in Group 17, with iodine being further down the group.

  3. 3

    b) Step 2: Iodine has more occupied principal electron shells than chlorine (5 shells for I vs 3 for Cl).

  4. 4

    b) Step 3: This means the outer electrons of iodine are further from the nucleus and experience more electron shielding from the inner electrons.

  5. 5

    b) Step 4: These factors outweigh the increased nuclear charge of iodine, resulting in a larger atomic radius.

Recap

  • The physical state at room temperature changes from gas (Cl₂) to liquid (Br₂) to solid (I₂).
  • The colour of the halogens darkens down the group.
  • Atomic radius increases down Group 17.
  • The increase in atomic radius is due to the increasing number of electron shells and the effect of electron shielding.

Quick check

  1. What is the trend in atomic radius down Group 17?1 mark
  2. What colour vapour is produced when solid iodine is gently heated?1 mark

4. Predicting Properties of Astatine

A key skill in chemistry is using periodic trends to predict the properties of unknown or less-common elements. Astatine (At) sits below iodine in Group 17. By extrapolating the trends we have observed for the other halogens, we can make educated predictions about its physical properties. Since melting/boiling points increase down the group, astatine will have a higher melting and boiling point than iodine, and will therefore be a solid at room temperature. Since the colours darken down the group (yellow -> green-yellow -> red-brown -> grey-black), astatine is predicted to be a black solid. Its volatility will be the lowest in the group, and its atomic radius will be the largest.

Key term

Extrapolation: The process of estimating a value by extending a known trend or pattern beyond the range of available data.

Examiner insight

When asked to predict properties, marks are awarded for both the prediction and the justification. Always explain your reasoning by referring to the established trend.

Fun fact

Astatine is the rarest naturally occurring element in the Earth's crust. It is so radioactive that the total amount present on Earth at any one time is estimated to be less than one gram!

Worked example 16 marks

Astatine (At) is in Group 17, below iodine. Predict the following properties of astatine, justifying your answers based on group trends:a) Physical state at 20°C.b) Boiling point relative to iodine.c) Atomic radius relative to iodine.

  1. 1

    a) Prediction: Solid. Justification: The melting and boiling points of the halogens increase down the group. Since iodine is a solid at 20°C, astatine, which is below it, will have an even higher melting point and will also be a solid.

  2. 2

    b) Prediction: Higher than iodine. Justification: Boiling point increases down the group due to stronger van der Waals' forces. Astatine molecules will have more electrons than iodine molecules, leading to stronger forces and a higher boiling point.

  3. 3

    c) Prediction: Larger than iodine. Justification: Atomic radius increases down the group because each successive element has an additional principal electron shell. Astatine will have one more shell than iodine, making its atomic radius larger.

Recap

  • Properties of elements can be predicted by extrapolating trends within their group.
  • Astatine is predicted to be a black solid at room temperature.
  • Astatine will have the highest boiling point in Group 17.
  • Astatine will have the largest atomic radius in Group 17.

Quick check

  1. Would you expect astatine to be more or less volatile than bromine?1 mark

5. Electronegativity and Oxidising Power

The chemical reactivity of the halogens is dominated by their tendency to gain an electron. This makes them powerful oxidising agents (they oxidise other substances by taking their electrons). The reactivity and oxidising power of the halogens decrease down the group. Fluorine is the most powerful oxidising agent, while iodine is the weakest. This trend is explained by changes in atomic structure. As you go down the group: 1. Atomic radius increases: The outer shell is further from the nucleus. 2. Electron shielding increases: There are more inner shells of electrons to shield the outer shell from the positive pull of the nucleus. These two factors mean that the nucleus has a weaker electrostatic attraction for a new electron. Although the nuclear charge increases down the group, the effects of increased distance and shielding are more significant. Therefore, it becomes progressively harder for atoms to attract and capture an electron as you descend the group, making them weaker oxidising agents.

General reduction half-equation: X₂ + 2e⁻ → 2X⁻

Key term

Oxidising Agent: A species that accepts electrons in a redox reaction, causing another species to be oxidised, while it is itself reduced.

Examiner insight

High-scoring answers clearly link the three key factors (atomic radius, shielding, nuclear attraction) to explain the trend in oxidising ability. Merely listing the factors is not enough.

Common pitfall

Simply stating that 'reactivity decreases down the group' without explaining this trend using the concepts of atomic radius, shielding, and nuclear attraction.

Worked example 14 marks

Explain why chlorine is a stronger oxidising agent than bromine.

  1. 1

    Step 1: Define the role of an oxidising agent. As an oxidising agent, a halogen atom accepts an electron.

  2. 2

    Step 2: Compare atomic radii. A chlorine atom has a smaller atomic radius than a bromine atom.

  3. 3

    Step 3: Compare electron shielding. A chlorine atom has fewer inner electron shells, so there is less electron shielding of the positive nucleus.

  4. 4

    Step 4: Link structure to attraction. Due to its smaller size and lower shielding, the nucleus of a chlorine atom exerts a stronger electrostatic force of attraction on an incoming electron compared to a bromine atom.

  5. 5

    Step 5: Conclude. Because it can attract an electron more strongly, chlorine is better at accepting electrons and is therefore a stronger oxidising agent than bromine.

Recap

  • The reactivity of halogens as oxidising agents decreases down the group (F > Cl > Br > I).
  • This trend is due to increasing atomic radius and electron shielding.
  • These factors weaken the electrostatic attraction between the nucleus and an incoming electron.
  • Fluorine is the most electronegative element and the strongest oxidising agent.

Quick check

  1. Which halogen is the weakest oxidising agent?1 mark
  2. Would a fluorine atom attract a bonding pair of electrons more or less strongly than a chlorine atom?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. State the physical state of chlorine, bromine and iodine at 20°C and 1 atm pressure.3 marks
  2. Place the following halogens in order of increasing boiling point: Bromine, Iodine, Chlorine. Explain your answer in terms of intermolecular forces.4 marks
  3. Explain, in terms of atomic structure, why the atomic radius of the halogens increases down Group 17.3 marks
  4. Astatine (At) is a halogen found below iodine in the Periodic Table. Predict the physical state and colour of astatine at room temperature. Justify your predictions.3 marks
  5. Explain why iodine has the highest boiling point of the halogens chlorine, bromine, and iodine.4 marks
  6. Define the term 'oxidising agent' and explain why bromine is a weaker oxidising agent than chlorine.4 marks
  7. The boiling point of fluorine (F₂) is -188°C while the boiling point of hydrogen fluoride (HF) is +20°C, despite F₂ having a much larger relative molecular mass. Explain this difference with reference to the types of intermolecular forces in each substance.4 marks
  8. A student makes the following statement: 'The covalent bond in an I₂ molecule is weak, which is why iodine is a solid with a low boiling point.' Identify and correct two errors in this statement.4 marks
  9. Describe and explain the trend in electronegativity down Group 17.3 marks
  10. Compare the volatility of Cl₂ and Br₂. Explain your reasoning.3 marks

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