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Cambridge IGCSE0580

Sequences

Mathematics 0580 Chapter Notes

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Sequences
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Sequences notes

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1. Continuing a sequence

To continue a sequence, find what happens from one term to the next. Subtract each term from the one after it. If the difference is the same every time, keep adding it. If the differences themselves change, look for a pattern in them. For 1, 3, 6, 10, 15 the differences are 2, 3, 4, 5, so the next two terms are 21 and 28.

In Extended work, Tn means the nth term of sequence T. So T₃ is the 3rd term. Write the new terms in order.

Examiner insight

“Errors were made in subtracting 6, usually resulting in –4 or –2 for the second of the terms.” “Some gave 40 and 47 which are the two numbers before the start of the sequence.”

Worked example 12 marks

Do not use a calculator.

These are the first four terms of a sequence.

27, 21, 15, 9

Find the next two terms in the sequence.

  1. 1

    each term is 6 less than the one before: 9 - 6 = 3 [1]

  2. 2

    3 - 6 = -3, so the next two terms are 3 and -3 in this order [1]

2. The term-to-term rule

The term-to-term rule tells you how to get from one term to the next. Write it in words, with an operation and a number: add 7, subtract 6, divide by 10. It is not the nth term: it has no n in it.

To find the rule, test the difference first. If the difference changes but each term is the same multiple of the one before, the rule is to multiply or divide.

Examiner insight

“Some candidates gave general expressions in terms of n, rather than providing a specific answer as required by the question.” “Answers of 3 × n, showed that candidates realised that multiplication by 3 was required but this is not how the term to term rule should be expressed.”

Worked example 11 mark

Do not use a calculator.

These are the first four terms of a sequence.

6000, 600, 60, 6

Write down the term-to-term rule for this sequence.

  1. 1

    6000 ÷ 10 = 600 and 600 ÷ 10 = 60, so the rule is divide by 10 [1]

3. Relationships between sequences

Two sequences can be linked term by term. If Cn = An + Bn, each term of C is the term of A plus the term of B in the same position.

Rearrange as you would an equation: An = Cn - Bn. Find the nth term of the sequence you know, then subtract. Take care with brackets when you subtract an expression.

Cn = An + Bn so An = Cn - Bn

Examiner insight

“A small number of candidates left sequence C blank, not spotting that it could be found from A – B or by working with the differences.”

Worked example 13 marks

Do not use a calculator.

A, B and C are linear sequences. The table gives some information about these sequences.

For these sequences, Cn = An + Bn.

Work out An, the nth term of sequence A.

sequence1st term2nd term3rd term4th termnth term
A3
B-4Bn = n - 5
C-1258
  1. 1

    C goes up by 3 each time and starts at -1, so Cn = 3n - 4 [1]

  2. 2

    An = Cn - Bn = 3n - 4 - (n - 5) [1]

  3. 3

    An = 2n + 1 [1]

4. The nth term of a linear sequence

In a linear sequence the terms go up or down by the same amount, the common difference d. The nth term is dn + c.

To find c, go back one step from the first term: c = first term - d. Check by putting n = 1 and n = 2 into your answer.

For a decreasing sequence d is negative. Once you have the nth term, set it equal to a number and solve to test whether that number is in the sequence. It is a term only if n is a whole number.

nth term = dn + c, c = first term - d

Examiner insight

“Many had learnt the expression, a + (n – 1)d but did not know how to substitute in the difference and the first term.” “Some checking by candidates, using substitution, may have helped identify any error.”

Worked example 14 marks

These are the first four terms of a sequence.

3, 7, 11, 15

(i) Find the nth term.

(ii) Show that 603 is a term in the sequence.

  1. 1

    (i) the terms go up by 4, so start with 4n [1]

  2. 2

    4 × 1 = 4 and the first term is 3, so the nth term is 4n - 1 [1]

  3. 3

    (ii) set 4n - 1 = 603 [1]

  4. 4

    n = (603 + 1)/4 = 151, a whole number, so 603 is the 151st term [1]

5. Using a given nth term

To find a term, put its position in place of n. For the first three terms use n = 1, n = 2 and n = 3. The first term is n = 1, not n = 0.

The nth term means the term in position n. It is not the 9th term. A formula such as 3n - 1 is the nth term, and a term is in the sequence if some whole n gives it.

Examiner insight

“Some candidates gave –3, 2, 7 from starting with n = 0 rather than n = 1.” “A few candidates seemed to think the nth term meant the ninth term as –18 was sometimes seen.”

Worked example 13 marks

The nth term of a sequence is 3n - 1.

(a) Write down the first 3 terms in this sequence.

(b) 327 and 331 are not in the sequence with nth term 3n - 1.

Write down all the numbers from the list that are in the sequence.

325, 326, 327, 328, 329, 330, 331, 332

  1. 1

    (a) n = 1, 2, 3 gives 3 - 1, 6 - 1, 9 - 1 = 2, 5, 8 [1]

  2. 2

    (b) every term is 1 less than a multiple of 3, so add 1 to each number: 327, 330, 333 are multiples of 3 [1]

  3. 3

    the numbers in the sequence are 326, 329 and 332 [1]

6. Quadratic and cubic sequences

A simple quadratic sequence compares with the square numbers 1, 4, 9, 16, 25. The simplest have nth term n² plus or minus a number. A simple cubic sequence compares with the cube numbers 1, 8, 27, 64. The simplest have nth term n³ plus or minus a number.

Write the square or cube numbers under the sequence and see what you must add or subtract. The differences between the terms are not constant, so a linear nth term does not fit. To use the nth term, square or cube n first: 1² = 1, not 2.

n² + c n³ + c

Examiner insight

“To find the formula for the quadratic many candidates did not spot the pattern in the terms and used the method of differences. Some candidates did not see the pattern of cubes in the third sequence.” “The other error occasionally seen was to think 1² = 2 then to give the first term as –1 instead of –2.”

Worked example 12 marks

Do not use a calculator.

Find the nth term of the sequence 2, 5, 10, 17, …

  1. 1

    the differences are 3, 5, 7, so the sequence is quadratic: compare with 1, 4, 9, 16 [1]

  2. 2

    each term is 1 more than n²: nth term = n² + 1 [1]

7. Exponential sequences

In an exponential sequence each term is the previous term multiplied by the same number. The term-to-term rule is multiply by that number.

The nth term has the form a × rⁿ⁻¹, where a is the first term and r is the number you multiply by. Do not write r × n: that is a linear sequence. Leave 4 × 3ⁿ⁻¹ as it is: it is not 12ⁿ⁻¹. Check your answer with n = 1 and n = 2.

a × rⁿ⁻¹

Examiner insight

“Some could not put the term-to-term rule of × 5 into an expression. Some gave the next term of 3125 as their answer.”

Worked example 12 marks

Do not use a calculator.

These are the first four terms of a sequence.

4, 12, 36, 108

Find the nth term of this sequence.

  1. 1

    each term is 3 times the one before, so the power of 3 is 3ⁿ⁻¹ [1]

  2. 2

    the first term is 4: nth term = 4 × 3ⁿ⁻¹ [1]

Recap

  • Subtract neighbouring terms to find the pattern, then continue it.
  • The term-to-term rule is in words: add, subtract, multiply or divide.
  • Cn = An + Bn gives An = Cn - Bn.
  • Linear: nth term = dn + c, with c = first term - d.
  • To use a given nth term, put n = 1, 2, 3 in turn. A number is a term only if n is a whole number.
  • Quadratic: compare with n². Cubic: compare with n³.
  • Extended: exponential sequences have nth term a × rⁿ⁻¹.

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Do not use a calculator. Write down the next two terms of the sequence 1, 3, 6, 10, 15, …2 marks
  2. Do not use a calculator. These are the first four terms of a sequence. 80, 40, 20, 10 Write down the next term and the term-to-term rule.2 marks
  3. Do not use a calculator. The nth term of sequence S is 4n - 2. Each term of sequence T is 3 more than the term of S in the same position. Write down the nth term of T.2 marks
  4. Do not use a calculator. Find the nth term of the sequence 7, 10, 13, 16, …2 marks
  5. These are the first four terms of a sequence. 20, 17, 14, 11 (a) Find the nth term. (b) Work out the 15th term.3 marks
  6. The nth term of a sequence is 5n - 2. Show that 143 is a term of the sequence, and show that 100 is not.3 marks
  7. Do not use a calculator. Find the nth term of the sequence 4, 7, 12, 19, …2 marks
  8. These are the first four terms of a sequence. 3, 10, 29, 66 (a) Find the nth term. (b) Work out the 12th term.3 marks
  9. Do not use a calculator. The first four terms of three sequences are given. Sequence A: 5, 9, 13, 17 Sequence B: 3, 6, 12, 24 Sequence D: 2, 3, 1, -7 (a) Find An and Bn. (b) Each term of D is made from the terms of A and B in the same position. Find Dn. (c) Work out D₇.6 marks
  10. A scientist counts the cells in two dishes at the start of each day. The counts on days 1, 2, 3 and 4 are given. Dish P: 7, 14, 28, 56 Dish Q: 151, 154, 159, 166 The patterns continue. (a) Find the nth term of each sequence. (b) Find the first day on which dish P holds more cells than dish Q. Show the values you compare. (c) Work out how many more cells dish P holds than dish Q on that day.7 marks

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