Cambridge Lower Secondary CheckpointStage 8

Geometry and Measure (8Gg)

Mathematics Stage 8 Chapter Notes

What this chapter covers

Geometry and Measure - Geometrical reasoning, shapes and measurements
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1. Angles on Parallel and Intersecting Lines

When a line, called a transversal, intersects two parallel lines, it creates pairs of angles with special relationships. 'Corresponding angles' are in the same position at each intersection and are equal. 'Alternate angles' are on opposite sides of the transversal and between the parallel lines, and are also equal. 'Vertically opposite angles' are formed when any two lines cross, and they are the angles opposite each other, which are always equal. Finally, 'co-interior angles' are on the same side of the transversal and between the parallel lines; they add up to 180°.

a = b (Corresponding angles)

c = d (Alternate angles)

e = f (Vertically opposite angles)

g + h = 180° (Co-interior angles)

Key term

Transversal: A line that intersects two or more other lines at different points.

Examiner insight

Examiners award marks for both the correct angle and the correct geometric reason. Simply writing the answer without the reason will not get you full marks.

Common pitfall

Confusing alternate and corresponding angles, especially when the diagram is rotated or complex. Use the F (corresponding) and Z (alternate) shapes to help identify them.

Worked example 13 marks

In the diagram, line L1 is parallel to line L2. Find the values of angles x, y, and z, giving reasons for each answer.

  1. 1

    Angle x is 110°. Reason: It is vertically opposite the given 110° angle, and vertically opposite angles are equal.

  2. 2

    Angle y is 110°. Reason: It corresponds to the given 110° angle, and corresponding angles on parallel lines are equal. (Alternatively, it is alternate to angle x).

  3. 3

    Angle z + 110° = 180°. Reason: Angles on a straight line add up to 180°.

  4. 4

    z = 180° - 110° = 70°.

Recap

  • Corresponding angles are equal (F-shape).
  • Alternate angles are equal (Z-shape).
  • Vertically opposite angles are equal (X-shape).
  • Co-interior angles add up to 180° (C-shape).
  • Always state the geometric reason for your answer.

Quick check

  1. If two parallel lines are cut by a transversal and one corresponding angle is 65°, what is the measure of the other?1 mark

2. Area of Parallelograms and Trapezia

To find the area of a parallelogram, you multiply its base by its perpendicular height. This works because you can imagine cutting a triangle from one end and moving it to the other to form a rectangle with the same base and height. A trapezium has one pair of parallel sides. To find its area, you first find the average of the two parallel sides (add them and divide by two), and then multiply by the perpendicular height. For both shapes, it is crucial to use the perpendicular height, not the slanted side length.

Area of parallelogram = base × perpendicular height

Area of trapezium = 1/2 × (a + b) × h

Key term

Perpendicular Height (h): The height of a shape measured at a right angle (90°) from its base.

Examiner insight

Marks are often lost for using a slanted side length instead of the perpendicular height. Always double-check that the height you use forms a right angle with the base.

Common pitfall

Forgetting to add the parallel sides of a trapezium before multiplying, or forgetting to multiply by 1/2.

Worked example 12 marks

Calculate the area of the trapezium shown, which has parallel sides of length 8 cm and 12 cm, and a perpendicular height of 7 cm.

  1. 1

    Write down the formula for the area of a trapezium: Area = 1/2 × (a +b) × h.

  2. 2

    Identify the values: a = 8 cm, b = 12 cm, h = 7 cm.

  3. 3

    Substitute the values into the formula: Area = 1/2 × (8 + 12) × 7.

  4. 4

    Calculate the sum in the brackets: Area = 1/2 × (20) × 7.

  5. 5

    Complete the calculation: Area = 10 × 7 = 70 cm².

Worked example 22 marks

A parallelogram has an area of 45 m² and a base of 9 m. What is its perpendicular height?

  1. 1

    Write down the formula: Area = base × height.

  2. 2

    Substitute the known values: 45 = 9 × h.

  3. 3

    Rearrange the formula to find the height: h = 45 ÷ 9.

  4. 4

    Calculate the result: h = 5 m.

Recap

  • The area of a parallelogram is base times perpendicular height.
  • The area of a trapezium is half the sum of the parallel sides, times the height.
  • Always use the perpendicular height, not a slanted side.
  • The parallel sides in a trapezium are 'a' and 'b' in the formula.

Quick check

  1. A parallelogram has a base of 10 cm and a perpendicular height of 4 cm. What is its area?1 mark

3. Circumference of a Circle

The circumference is the distance around the outside of a circle, essentially its perimeter. There is a special relationship between a circle's circumference and its diameter (the distance across the circle through its center). The ratio of the circumference to the diameter is always the same number, called Pi (π). Pi is an irrational number, approximately 3.14159. The radius is the distance from the center to the edge, which is half the diameter.

C = πd

C = 2πr

d = 2r

Key term

Pi (π): The constant ratio of a circle's circumference to its diameter, approximately equal to 3.14159.

Common pitfall

Mixing up the radius and diameter. A common mistake is to use C = πr instead of C = 2πr. Always double-check which measurement you are given.

Fun fact

The digits of Pi never repeat and go on forever. The current world record for calculating its digits is over 100 trillion!

Worked example 12 marks

A circle has a radius of 5 cm. Calculate its circumference, leaving your answer in terms of π.

  1. 1

    Identify the correct formula to use. Since we have the radius, we use C = 2πr.

  2. 2

    Substitute the value of the radius: r = 5 cm.

  3. 3

    C = 2 × π × 5.

  4. 4

    Simplify the expression: C = 10π cm.

Worked example 23 marks

The circumference of a bicycle wheel is 188.5 cm. Calculate its diameter to the nearest whole number. (Use π = 3.14)

  1. 1

    Start with the formula involving circumference and diameter: C = πd.

  2. 2

    Substitute the known values: 188.5 = 3.14 × d.

  3. 3

    Rearrange the formula to find the diameter: d = 188.5 ÷ 3.14.

  4. 4

    Calculate the result: d = 60.03... cm.

  5. 5

    Round to the nearest whole number: d = 60 cm.

Recap

  • The circumference is the perimeter of a circle.
  • The diameter is twice the radius (d = 2r).
  • Use C = πd when you know the diameter.
  • Use C = 2πr when you know the radius.
  • Check if the question asks for the answer in terms of π or as a decimal.

Quick check

  1. What is the formula for the circumference of a circle using its diameter, d?1 mark

4. Volume of Prisms

A prism is a 3D shape that has a constant cross-section. This means if you slice it anywhere along its length, the 2D shape of the slice is always the same. Examples include cuboids, cylinders, and triangular prisms. The volume of any prism is found using a simple, powerful formula: multiply the area of its cross-section by its length (or height). For a triangular prism, the cross-section is a triangle, so you find the area of the triangle first (1/2 × base × height) and then multiply that by the length of the prism.

Volume of any prism = Area of cross-section × length

Volume of triangular prism = (1/2 × base × height) × length

Key term

Cross-section: The 2D shape revealed when a straight cut is made through a 3D object.

Examiner insight

Show your working by calculating the area of the cross-section first, then multiplying by the length. This two-step process can earn partial marks even if you make a final calculation error.

Common pitfall

Confusing the 'height' of the triangular face with the 'length' of the prism. Label them carefully on your diagram before you start.

Worked example 13 marks

Calculate the volume of the triangular prism shown. The triangular face has a base of 6 cm and a perpendicular height of 4 cm. The length of the prism is 10 cm.

  1. 1

    First, calculate the area of the cross-section (the triangle).

  2. 2

    Area of triangle = 1/2 × base × height = 1/2 × 6 cm × 4 cm = 12 cm².

  3. 3

    Now, use the formula for the volume of a prism: Volume = Area of cross-section × length.

  4. 4

    Substitute the values: Volume = 12 cm² × 10 cm.

  5. 5

    Calculate the final volume: Volume = 120 cm³.

Recap

  • A prism has a constant cross-section along its length.
  • The volume of any prism is the area of its cross-section multiplied by its length.
  • For a triangular prism, first find the area of the triangle face.
  • Remember that volume is measured in cubic units, such as cm³ or m³.

Quick check

  1. A prism has a cross-sectional area of 25 cm² and a length of 8 cm. What is its volume?1 mark

5. Surface Area of 3D Shapes

The surface area of a 3D shape is the total area of all its individual faces added together. A helpful way to think about it is to imagine unfolding the shape into a flat 2D pattern, called a 'net'. You then find the area of each piece of the net and sum them up. For a cuboid, you have 3 pairs of identical rectangular faces (top/bottom, front/back, left/right). For a triangular prism, you have two identical triangles and three rectangles. For a pyramid, you have a base and several triangular faces.

Surface Area of Cuboid = 2(lw + lh + wh)

Surface Area of Cube = 6l²

Key term

Net: A 2D pattern of faces that can be folded to make a 3D shape.

Examiner insight

A good strategy is to list the areas of all the faces (e.g., 'front', 'back', 'top', 'bottom', 'left', 'right') before adding them up to ensure none are missed. This systematic approach is rewarded.

Common pitfall

Forgetting to include all the faces in the calculation, especially the hidden ones like the bottom of a cuboid or the different rectangles on a triangular prism.

Worked example 13 marks

Find the total surface area of a cuboid with length 5 cm, width 3 cm, and height 4 cm.

  1. 1

    Identify the areas of the three pairs of faces.

  2. 2

    Area of front and back faces = 2 × (length × height) = 2 × (5 × 4) = 40 cm².

  3. 3

    Area of top and bottom faces = 2 × (length × width) = 2 × (5 × 3) = 30 cm².

  4. 4

    Area of left and right faces = 2 × (width × height) = 2 × (3 × 4) = 24 cm².

  5. 5

    Add the areas of all faces together: Total Surface Area = 40 + 30 + 24 = 94 cm².

Worked example 24 marks

Find the surface area of a triangular prism. The ends are right-angled triangles with sides 3cm, 4cm, 5cm. The length of the prism is 10cm.

  1. 1

    Area of two triangular ends = 2 × (1/2 × base × height) = 2 × (1/2 × 3 × 4) = 12 cm².

  2. 2

    Area of the rectangular base = base × length = 3 cm × 10 cm = 30 cm².

  3. 3

    Area of the rectangular back = height × length = 4 cm × 10 cm = 40 cm².

  4. 4

    Area of the slanted rectangular face = hypotenuse × length = 5 cm × 10 cm = 50 cm².

  5. 5

    Total Surface Area = 12 + 30 + 40 + 50 = 132 cm².

Recap

  • Surface area is the total area of all faces of a 3D shape.
  • Imagine unfolding the shape into a net to make sure you count all faces.
  • A cuboid has 6 faces (3 pairs of identical rectangles).
  • A triangular prism has 5 faces (2 triangles and 3 rectangles).
  • A square-based pyramid has 5 faces (1 square and 4 triangles).

Quick check

  1. A cube has an edge length of 2 cm. What is its total surface area?2 marks

6. Properties of 3D Shapes and Euler's Formula

Polyhedra (3D shapes with flat faces) can be described by their number of faces (F), vertices (V), and edges (E). A face is a flat surface, a vertex is a corner where edges meet, and an edge is a line segment where two faces meet. A remarkable mathematician named Leonhard Euler discovered a simple formula that connects these three properties for all convex polyhedra: the number of vertices minus the number of edges plus the number of faces always equals 2.

V - E + F = 2

Key term

Vertex (plural: Vertices): A point where two or more edges of a 3D shape meet; a corner.

Common pitfall

Miscounting the number of edges on a complex shape. A good technique is to count the edges on the top and bottom faces, and then the vertical edges connecting them.

Fun fact

This simple formula, V - E + F = 2, works for a simple cube just as well as it does for the complex pattern on a soccer ball (a truncated icosahedron), which has 32 faces, 60 vertices, and 90 edges (60 - 90 + 32 = 2).

Worked example 12 marks

A standard cuboid has 6 faces, 8 vertices, and 12 edges. Verify that Euler's formula holds true.

  1. 1

    State Euler's formula: V - E + F = 2.

  2. 2

    Substitute the values for a cuboid: V = 8, E = 12, F = 6.

  3. 3

    Calculate the left side of the equation: 8 - 12 + 6.

  4. 4

    8 - 12 = -4. Then -4 + 6 = 2.

  5. 5

    Since the result is 2, the formula holds true for a cuboid.

Worked example 22 marks

A polyhedron has 12 faces and 30 edges. How many vertices does it have?

  1. 1

    Start with Euler's formula: V - E + F = 2.

  2. 2

    Substitute the known values: V - 30 + 12 = 2.

  3. 3

    Simplify the equation: V - 18 = 2.

  4. 4

    Solve for V by adding 18 to both sides: V = 2 + 18.

  5. 5

    V = 20. The polyhedron has 20 vertices.

Recap

  • F stands for Faces (the flat surfaces).
  • V stands for Vertices (the corners).
  • E stands for Edges (the lines where faces meet).
  • Euler's formula for polyhedra is V - E + F = 2.

Quick check

  1. A triangular pyramid has 4 vertices and 4 faces. How many edges does it have?2 marks

7. Converting Miles and Kilometres

Miles and kilometres are both units used to measure long distances. Miles are part of the imperial system (used in the UK, USA), while kilometres are part of the metric system (used by most of the world). It's essential to be able to convert between them. The key approximation to remember is that 1 mile is about 1.6 kilometres. This means for the same distance, the number of kilometres will be larger than the number of miles. A useful fraction approximation is that 5 miles is roughly equal to 8 kilometres.

Kilometres ≈ Miles × 1.6

Miles ≈ Kilometres ÷ 1.6

8 kilometres ≈ 5 miles

Key term

Conversion Factor: A number used to change one set of units to another by multiplying or dividing.

Examiner insight

Using the 5 miles ≈ 8 km relationship can be very fast, especially in non-calculator questions. For example, to convert 40 miles to km, you can do (40 ÷ 5) × 8 = 8 × 8 = 64 km.

Common pitfall

Multiplying when you should be dividing, or vice-versa. Remember: 'Kilometres are longer' (the word is longer), so the number of km for a given distance is always bigger than the number of miles.

Worked example 12 marks

A signpost says the next town is 30 miles away. How far is this in kilometres?

  1. 1

    To convert from miles to kilometres, we multiply by 1.6.

  2. 2

    Distance in km = Distance in miles × 1.6.

  3. 3

    Distance in km = 30 × 1.6.

  4. 4

    Calculation: 30 × 1 = 30, and 30 × 0.6 = 18. So, 30 + 18 = 48.

  5. 5

    The distance is 48 km.

Worked example 22 marks

The marathon is a race of 42.2 kilometres. What is this distance in miles, to one decimal place?

  1. 1

    To convert from kilometres to miles, we divide by 1.6.

  2. 2

    Distance in miles = Distance in km ÷ 1.6.

  3. 3

    Distance in miles = 42.2 ÷ 1.6.

  4. 4

    Calculation: 42.2 ÷ 1.6 = 26.375.

  5. 5

    Round to one decimal place: 26.4 miles.

Recap

  • 1 mile is approximately 1.6 kilometres.
  • 5 miles is approximately 8 kilometres.
  • To convert miles to km, multiply by 1.6 (the number gets bigger).
  • To convert km to miles, divide by 1.6 (the number gets smaller).
  • The fraction 5/8 can be used to convert km to miles, and 8/5 for miles to km.

Quick check

  1. Approximately how many kilometres are in 10 miles?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. In the diagram, line AB is parallel to line CD. Angle BEF is 48°. Find the size of angle EFG, giving a reason for your answer.2 marks
  2. The distance between two cities is 250 miles. Convert this distance to kilometres.2 marks
  3. Calculate the area of a trapezium with parallel sides of 9 cm and 15 cm, and a perpendicular height of 8 cm.2 marks
  4. A triangular prism has a volume of 150 cm³. The area of its triangular cross-section is 10 cm². What is the length of the prism?2 marks
  5. A polyhedron has 20 vertices and 12 faces. Use Euler's formula (V - E + F = 2) to find the number of edges it has.2 marks
  6. A circular pond has a diameter of 8 metres. Calculate its circumference, giving your answer to one decimal place. (Use π = 3.142)3 marks
  7. Calculate the total surface area of a cuboid that is 10 cm long, 7 cm wide, and 4 cm high.3 marks
  8. A running track is formed by a rectangle measuring 90 m by 70 m, with a semicircle on each of the 70 m sides. Calculate the total perimeter of the track.4 marks
  9. Calculate the surface area of a triangular prism. Its length is 20 cm. The cross-section is a right-angled triangle with a base of 12 cm, a height of 5 cm, and a hypotenuse of 13 cm.4 marks
  10. The area of the parallelogram shown is 54 cm². Its base is 9 cm. A triangle with a base of 6 cm is attached. If the total area of the compound shape is 66 cm², what is the height of the triangle (x)?4 marks

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