Cambridge IGCSE0972

Physical quantities and measurement techniques

Physics 0972 Chapter Notes

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Physical quantities and measurement techniques
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1. Physical Quantities, Units and Prefixes

In physics, every measurement is a 'physical quantity', which consists of two parts: a numerical value (its magnitude) and a unit. For example, in '10 metres', 10 is the magnitude and 'metres' is the unit. To ensure scientists worldwide can understand each other, a standard system called SI units (Système International d'Unités) is used. The base SI units for the three most common quantities are the metre(m) for length, the kilogram (kg) for mass, and the second(s) for time. Sometimes, a quantity is very large or very small, so we use prefixes to modify the unit. For example, 'kilo'(k) means 1000 times bigger, so 1 kilometre (km) is 1000 metres. 'Milli'(m) means 1000 times smaller, so 1 millimetre (mm) is 0.001 metres. It is crucial to convert all quantities into their base SI units before using them in most physics equations.

Key term

Physical Quantity: A property of a material or system that can be quantified by measurement, expressed as a magnitude and a unit.

Examiner insight

Examiners expect you to consistently include the correct units with every numerical answer in a calculation. A correct number with a missing or wrong unit will lose marks.

Common pitfall

Forgetting to convert all quantities to their base SI units (e.g., cm to m, g to kg) before substituting them into a formula.

Fun fact

The kilogram was the last SI base unit to be defined by a physical object, the 'International Prototype Kilogram', until it was redefined in 2019 based on a fundamental constant of nature.

Worked example 13 marks

A car is travelling at a speed of 72 km/h. Convert this speed into the SI base units of m/s.

  1. 1

    Step 1: Identify the conversions needed. We need to convert kilometres (km) to metres(m) and hours(h) to seconds (s).

  2. 2

    Step 2: Convert the distance. 1 km = 1000 m. So, 72 km = 72 × 1000 m = 72000 m.

  3. 3

    Step 3: Convert the time. 1 hour = 60 minutes, and 1 minute = 60 seconds. So, 1 hour = 60 × 60 s = 3600 s.

  4. 4

    Step 4: Calculate the speed in m/s. Speed = Distance / Time = 72000 m / 3600 s.

  5. 5

    Step 5: Final answer. 72000 / 3600 = 20 m/s.

Recap

  • A physical quantity always has a magnitude (a number) and a unit.
  • The SI base unit for length is the metre (m), for mass is the kilogram (kg), and for time is the second (s).
  • Prefixes are used to scale units for very large or small measurements (e.g., kilo-, centi-, milli-).
  • Always convert units to standard SI form before performing calculations to avoid errors.

Quick check

  1. Convert 500 grams (g) into kilograms (kg).1 mark
  2. How many centimetres (cm) are in 1.5 metres (m)?1 mark

2. Measuring Length and Area

Length is a fundamental measurement of distance. For everyday lengths in the lab, a metre rule or a 30 cm ruler is used. These are typically marked in centimetres (cm) and millimetres (mm). To measure accurately, you must avoid parallax error. This is an apparent shift in the object's position due to viewing the scale from an angle. To prevent this, always position your eye directly above the marking on the scale. The precision of a standard ruler is to the nearest millimetre. To measure very small thicknesses accurately, like a single sheet of paper, you should measure the thickness of a large stack (e.g., 500 sheets) and then divide the total thickness by the number of sheets. Area is the measure of a two-dimensional surface, calculated from length measurements. For a rectangle, it is length × width.

Area of a rectangle = length × width

Area of a triangle = ½ × base × height

Key term

Parallax Error: An apparent shift in the position of an object caused by a change in the observer's line of sight; it is avoided by reading a scale directly from the front at eye level.

Examiner insight

Marks are often awarded for describing a method to improve the accuracy of a length measurement. Stating 'measure a stack of items and divide' is a classic way to demonstrate this understanding.

Common pitfall

Stating the precision of a standard ruler is 1 cm instead of the more accurate 1 mm (or 0.1 cm).

Worked example 13 marks

A student measures the thickness of a textbook with 400 pages and finds it to be 2.8 cm (excluding the covers). Calculate the average thickness of a single sheet of paper in millimetres.

  1. 1

    Step 1: Note the total number of pages is 400. A sheet of paper consists of 2 pages (front and back). So, the number of sheets is 400 / 2 = 200 sheets.

  2. 2

    Step 2: Convert the total thickness to millimetres. 1 cm = 10 mm, so 2.8 cm = 2.8 × 10 = 28 mm.

  3. 3

    Step 3: Calculate the average thickness of one sheet. Average thickness = Total thickness / Number of sheets.

  4. 4

    Step 4: Substitute the values: Average thickness = 28 mm / 200 sheets.

  5. 5

    Step 5: Final answer. Average thickness = 0.14 mm.

Recap

  • Use a metre rule to measure lengths to the nearest millimetre.
  • Avoid parallax error by ensuring your line of sight is perpendicular to the scale.
  • To find the thickness of one sheet, measure a stack and divide by the number of sheets.
  • The area of a rectangle is found by multiplying its length and width.

Quick check

  1. A pencil lies next to a ruler. Its tip is at the 3.5 cm mark and its end is at the 12.0 cm mark. What is the length of the pencil?1 mark

3. Measuring Volume

Volume is the amount of three-dimensional space an object occupies. The method for measuring it depends on the object's state and shape. For liquids, a measuring cylinder is used. Pour the liquid in and take the reading from the scale. For water and most liquids, the surface curves downwards, forming a meniscus. Your eye should be level with the bottom of the meniscus to get an accurate reading. For a regular solid, like a rectangular block, you can calculate its volume by measuring its length (l), width (w), and height(h) with a ruler and using the formula V = l × w × h. For an irregular solid (like a stone), you must use the displacement method. Submerge the object in a measuring cylinder of water and measure the volume of the water displaced, which is equal to the object's volume. The volume is the difference between the final water level and the initial water level.

Volume of a cuboid = length × width × height

Volume of object = Final water level - Initial water level

Key term

Meniscus: The curved upper surface of a liquid in a tube, which should be read from the bottom for water to ensure an accurate volume measurement.

Examiner insight

Examiners look for a clear description of the displacement method, including reading the initial volume, fully submerging the object without splashing, and reading the final volume.

Common pitfall

Forgetting to subtract the initial volume of water from the final volume when using the displacement method.

Worked example 12 marks

A student wants to find the volume of a small, irregular stone. They pour 50 cm³ of water into a measuring cylinder. After carefully placing the stone into the cylinder, the water level rises to 72 cm³. What is the volume of the stone?

  1. 1

    Step 1: Identify the initial volume of water. V_initial = 50 cm³.

  2. 2

    Step 2: Identify the final volume of water and stone. V_final = 72 cm³.

  3. 3

    Step 3: The volume of the stone is the difference between the final and initial volumes. Volume of stone = V_final - V_initial.

  4. 4

    Step 4: Substitute the values: Volume of stone = 72 cm³ - 50 cm³.

  5. 5

    Step 5: Final answer. Volume of stone = 22 cm³.

Recap

  • Measure the volume of a liquid using a measuring cylinder.
  • Read the bottom of the meniscus at eye level to get an accurate reading for water.
  • Calculate the volume of a regular solid using the formula V = l × w × h.
  • Find the volume of an irregular solid using the water displacement method.

Quick check

  1. What two pieces of apparatus would you need to find the volume of a small, irregular stone?2 marks

4. Measuring Time and Improving Precision

Time is measured using a stopwatch or stopclock, which can measure to a precision of 0.1 s or 0.01 s. However, the main source of error is human reaction time when starting and stopping the clock. This error can be significant for short time intervals. To improve the precision of a time measurement for a repeating event, like a swinging pendulum, you should measure the time for a large number of complete cycles (e.g., 20 or 50 swings) and then divide the total time by the number of cycles. This calculates the average time for one cycle, known as the period. This technique makes the reaction time error at the start and end a much smaller fraction of the total time measured, greatly increasing the accuracy of the result for the period. Another potential error is a zero error, where the stopwatch does not start from exactly zero. Always check and, if possible, reset the device before starting.

Period (T) = Total time taken / Number of oscillations

Key term

Period: The time taken to complete one full cycle of an oscillation or repeating event.

Examiner insight

Describing a method to find an accurate period is a classic practical question. Stating 'time 20 swings and divide by 20' is the standard, expected answer for full marks.

Common pitfall

Timing only one swing of a pendulum. This is highly inaccurate due to the large percentage error from human reaction time.

Worked example 12 marks

A student measures the time taken for a simple pendulum to complete 20 full swings. The stopwatch reading is 35.0 s. Calculate the period of the pendulum.

  1. 1

    Step 1: Identify the total time measured and the number of swings.

  2. 2

    Total time = 35.0 s

  3. 3

    Number of swings (oscillations) = 20

  4. 4

    Step 2: State the formula for the period. Period = Total time / Number of swings.

  5. 5

    Step 3: Substitute the values into the formula. Period = 35.0 s / 20.

  6. 6

    Step 4: Calculate the final answer. Period = 1.75 s.

Recap

  • Use a stopwatch to measure time intervals.
  • Human reaction time is a major source of error in timing.
  • To accurately find the period of an oscillation, time a large number of swings (e.g., 20) and divide.
  • The period is the time for one complete oscillation.

Quick check

  1. Why is it more accurate to time 20 swings of a pendulum and divide by 20, rather than timing just one swing?1 mark

5. Understanding Mass and Density

Mass is a measure of the amount of matter in an object. It is a fundamental property and does not change with location. The SI unit for mass is the kilogram (kg). In the lab, mass is measured using a top-pan balance. Before placing an object on the balance, you should press the 'tare' or 'zero' button to ensure it starts from zero. Density is a derived quantity that describes how much mass is packed into a given volume. An object made of a dense material (like lead) has a lot of mass in a small space, while an object of a low-density material (like foam) has little mass in the same space. It is calculated by dividing an object's mass by its volume. The SI unit for density is kilograms per cubic metre (kg/m³), but grams per cubic centimetre (g/cm³) is also commonly used.

Density (ρ) = Mass (m) / Volume (V)

Key term

Density: The mass per unit volume of a substance, which is a measure of how compact the matter is.

Common pitfall

Confusing mass and weight. Mass is the amount of matter (in kg), while weight is the force of gravity on that mass (in N).

Fun fact

Osmium is the densest naturally occurring element. A piece the size of a mobile phone would have a mass of about 3.4 kg, feeling as heavy as a large brick.

Worked example 12 marks

A block of aluminium has a mass of 540 g and a volume of 200 cm³. Calculate its density in g/cm³.

  1. 1

    Step 1: State the formula for density. Density = Mass / Volume.

  2. 2

    Step 2: Identify the given values. Mass(m) = 540 g, Volume (V) = 200 cm³.

  3. 3

    Step 3: Substitute the values into the formula. Density = 540 g / 200 cm³.

  4. 4

    Step 4: Calculate the final answer. Density = 2.7 g/cm³.

Worked example 23 marks

Mercury has a density of 13.6 g/cm³. What is the mass of 50 cm³ of mercury?

  1. 1

    Step 1: State the formula for density. Density (ρ) = Mass(m) / Volume (V).

  2. 2

    Step 2: Rearrange the formula to make mass the subject. Mass(m) = Density (ρ) × Volume (V).

  3. 3

    Step 3: Identify the given values. Density (ρ) = 13.6 g/cm³, Volume (V) = 50 cm³.

  4. 4

    Step 4: Substitute the values into the rearranged formula. Mass = 13.6 g/cm³ × 50 cm³.

  5. 5

    Step 5: Calculate the final answer. Mass = 680 g.

Recap

  • Mass is the amount of matter in an object, measured in kilograms (kg).
  • Use a top-pan balance to measure mass, and tare it before use.
  • Density is mass per unit volume (ρ = m/V).
  • Density describes how 'compact' a substance is.
  • Ensure units for mass and volume are consistent before calculating density.

Quick check

  1. What physical quantity does a top-pan balance measure?1 mark
  2. An object has a mass of 100 g and a volume of 50 cm³. What is its density?1 mark

6. Determining Density Experimentally

To find the density of any object, you need to measure two quantities: its mass and its volume. The procedure combines the techniques learned in previous sections. For a regular solid (e.g., a metal cube): 1. Measure its mass using a top-pan balance. 2. Measure its length, width, and height using a ruler. 3. Calculate its volume using V = l × w × h. 4. Calculate density using ρ = m/V. For an irregular solid (e.g., a stone): 1. Measure its mass using a top-pan balance. 2. Find its volume using the displacement method with a measuring cylinder and water. 3. Calculate density using ρ = m/V. For a liquid: 1. Place an empty measuring cylinder on a top-pan balance and tare it (set to zero). 2. Pour the liquid into the measuring cylinder and record its mass. 3. Read the volume of the liquid from the cylinder's scale. 4. Calculate density using ρ = m/V.

Density (ρ) = Mass (m) / Volume (V)

Key term

Displacement Method: A technique used to measure the volume of an irregular object by measuring the volume of fluid it displaces when fully submerged.

Examiner insight

For questions asking you to describe an experiment, examiners award marks for a logical sequence of steps, naming the correct apparatus, and stating the formula used for the final calculation.

Common pitfall

When finding the density of a liquid, students forget to subtract the mass of the measuring cylinder itself, or they measure the mass of the cylinder before taring the balance.

Worked example 14 marks

Describe the experiment you would perform to determine the density of a small, irregularly shaped stone.

  1. 1

    Step 1: Measure the mass of the stone using a top-pan balance and record it in grams (g).

  2. 2

    Step 2: Partially fill a measuring cylinder with water and record the initial volume, V1, in cm³, ensuring your eye is level with the meniscus.

  3. 3

    Step 3: Carefully slide the stone into the measuring cylinder, ensuring it is fully submerged and no water splashes out.

  4. 4

    Step 4: Record the new water level, V2, in cm³.

  5. 5

    Step 5: Calculate the volume of the stone by subtracting the initial volume from the final volume: V = V2 - V1.

  6. 6

    Step 6: Calculate the density (ρ) using the formula ρ = mass / volume.

Recap

  • To find density, you must measure both mass and volume.
  • For a regular solid, measure dimensions to calculate volume.
  • For an irregular solid, use the displacement method to find volume.
  • For a liquid, measure the mass and volume of a sample directly.
  • Always ensure your units for mass and volume are consistent (e.g., g and cm³, or kg and m³).

Quick check

  1. To find the density of a liquid, you measure the mass of a measuring cylinder as 120 g. With the liquid inside, the mass is 160 g. The volume of the liquid is 50 cm³. What is the liquid's density?2 marks

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Convert the following quantities: (a) 2.5 km into m. (b) 300 g into kg. (c) 120 minutes into seconds.3 marks
  2. A student measures the length of a piece of wire to be 15.2 cm. When they look at the ruler from an angle, the reading appears to be 15.4 cm. What is the name of this error and how can it be avoided?2 marks
  3. A rectangular block of wood measures 20 cm by 10 cm by 5 cm. Calculate its volume in cm³ and in m³.3 marks
  4. To find the period of a spring's oscillation, a student times 50 complete oscillations. The total time recorded is 75.0 s. Calculate the period of the oscillation.2 marks
  5. An irregular piece of metal has a mass of 270 g. It is placed in a measuring cylinder that contains 100 cm³ of water. The water level rises to 130 cm³. Calculate the density of the metal in g/cm³.3 marks
  6. Describe, in steps, how you would accurately determine the density of a regular wooden block. State the apparatus you would use and the formula you would apply.4 marks
  7. A liquid has a density of 1200 kg/m³. Calculate the volume occupied by 60 kg of this liquid.3 marks
  8. The density of ice is 920 kg/m³ and the density of sea water is 1025 kg/m³. Explain why icebergs float in the sea.2 marks
  9. A perfect cube of a substance has a side length of 3.0 cm and a mass of 216 g. Calculate the density of the substance.3 marks
  10. A large cylindrical oil tank has a base area of 20 m² and is filled to a height of 5 m with oil of density 850 kg/m³. Calculate the total mass of the oil in the tank in tonnes (1 tonne = 1000 kg).4 marks

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