1. Understanding Work Done
In physics, 'work' has a very specific meaning. Work is done whenever a force causes an object to move. It is the transfer of energy from one form to another. For work to be done, two conditions must be met: there must be a force, and the object must move in the direction of the force. The amount of work done is calculated as the product of the force and the distance moved in the direction of the force. If you push against a wall and it doesn't move, you have done no work on the wall, even though you might feel tired! The unit of work is the Joule (J). One Joule is the work done when a force of 1 Newton moves an object by 1 metre. If the force acts at an angle to the direction of motion, we only consider the component of the force that is in the direction of motion. This is calculated using `W = Fs cos(θ)`, where θ is the angle between the force and the displacement.
W = Fs
W = Fs cos(θ)
Key term
Examiner insight
Common pitfall
Worked example 13 marks
A student pulls a block of mass 5.0 kg along a horizontal surface for a distance of 8.0 m. The student pulls with a rope that exerts a tension of 40 N at an angle of 30° to the horizontal. Calculate the work done by the student on the block.
- 1
Step 1: Identify the formula. The force is at an angle to the displacement, so we use W = Fs cos(θ).
- 2
Step 2: Identify the values. F = 40 N, s = 8.0 m, θ = 30°.
- 3
Step 3: Calculate the horizontal component of the force: F_horizontal = F cos(θ) = 40 cos(30°).
- 4
Step 4: Calculate the work done: W = (40 cos(30°)) × 8.0 or W = 40 × 8.0 × cos(30°).
- 5
Step 5: W = 40 × 8.0 × 0.866 = 277.1 J. Rounding to 2 significant figures gives 280 J.
Recap
- Work is done when a force causes displacement.
- The unit of work is the Joule (J).
- Work done = Force × distance moved in the direction of the force (W = Fs).
- If the force is at an angle θ to the displacement, use W = Fs cos(θ).
- No work is done if the object does not move (s=0).
- No work is done by a force that is perpendicular to the direction of motion (cos(90°) = 0).
Quick check
- A crane lifts a 1000 kg load vertically by 15 m. How much work is done by the lifting force? (Take g = 9.81 N/kg)2 marks