Cambridge IGCSE0620

The characteristic properties of acids and bases

Chemistry 0620 Chapter Notes

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The characteristic properties of acids and basesOxidesPreparation of salts
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1. Introduction to Acids and Alkalis

Acids are substances that form hydrogen ions (H⁺) when dissolved in water. Common laboratory acids include hydrochloric acid (HCl), sulfuric acid (H₂SO₄), and nitric acid (HNO₃). They are corrosive, taste sour, and have a pH less than 7. Alkalis are bases that are soluble in water. They form hydroxide ions (OH⁻) in solution. Common alkalis include sodium hydroxide (NaOH), potassium hydroxide (KOH), and aqueous ammonia (NH₃). They feel soapy, are corrosive, and have a pH greater than 7. Indicators are substances that change colour depending on the pH. Litmus paper turns red in acid and blue in alkali. Methyl orange turns red in acid and yellow in alkali. The pH scale, from 0 to 14, measures acidity and alkalinity. A pH of 7 is neutral (like pure water), values below 7 are acidic (the lower the number, the more acidic), and values above 7 are alkaline (the higher the number, the more alkaline). Universal indicator has a range of colours corresponding to the entire pH scale, from red for strong acids to dark purple for strong alkalis.

Acid: produces H⁺(aq) ions in water.

Alkali: produces OH⁻(aq) ions in water.

Key term

pH Scale: A logarithmic scale from 0 to 14 that measures the acidity or alkalinity of an aqueous solution.

Examiner insight

Examiners expect you to know the specific colour changes for litmus and methyl orange in both acidic and alkaline conditions, not just that they 'change colour'.

Common pitfall

Confusing an alkali with a base. All alkalis are bases, but not all bases are alkalis because not all bases are soluble in water (e.g., copper(II) oxide is a base but not an alkali).

Fun fact

Your stomach contains hydrochloric acid with a pH of 1.5 to 3.5, which is strong enough to dissolve razor blades, though it happens over many hours.

Worked example 14 marks

A student tests three unknown colourless solutions, X, Y, and Z, with Universal Indicator. Solution X turns red, solution Y turns green, and solution Z turns blue.(a) Identify which solution is acidic, alkaline, and neutral.(b) State the colour that litmus paper would turn in solution X and solution Z.

  1. 1

    (a) The pH scale and Universal Indicator colours show: red is strongly acidic (pH ~1-2), green is neutral (pH 7), and blue is alkaline (pH ~8-11).

  2. 2

    Therefore, solution X is acidic, solution Y is neutral, and solution Z is alkaline.

  3. 3

    (b) Litmus paper turns red in acidic solutions and blue in alkaline solutions.

  4. 4

    In solution X (acidic), litmus paper will turn red.

  5. 5

    In solution Z (alkaline), litmus paper will turn blue.

Recap

  • Acids produce H⁺ ions in water and have a pH below 7.
  • Alkalis are soluble bases that produce OH⁻ ions in water and have a pH above 7.
  • Litmus is red in acid and blue in alkali; Methyl orange is red in acid and yellow in alkali.
  • The pH scale runs from 0 (very acidic) to 14 (very alkaline), with 7 being neutral.
  • Common acids are HCl, H₂SO₄, and HNO₃; common alkalis are NaOH, KOH, and NH₃(aq).

Quick check

  1. What is the chemical formula for calcium hydroxide?1 mark
  2. What colour is methyl orange indicator in a solution of sodium hydroxide?1 mark

2. Typical Reactions of Acids

Acids take part in several characteristic reactions, typically producing a salt. A salt is an ionic compound formed when the hydrogen of an acid is replaced by a metal or ammonium ion. The name of the salt depends on the acid used: hydrochloric acid produces chlorides, sulfuric acid produces sulfates, and nitric acid produces nitrates. There are three key general reactions to learn.

Acid + Metal → Salt + Hydrogen

Acid + Base → Salt + Water

Acid + Carbonate → Salt + Water + Carbon Dioxide

Key term

Salt: An ionic compound formed when the hydrogen ion in an acid is replaced by a metal ion or an ammonium ion.

Examiner insight

Marks are often awarded for correctly identifying the products of a reaction, especially the gas produced (hydrogen with metals, carbon dioxide with carbonates) and its chemical test.

Common pitfall

Forgetting to include water as a product in acid-base and acid-carbonate reactions.

Worked example 13 marks

Write the balanced chemical equation for the reaction between nitric acid (HNO₃) and insoluble copper(II) oxide (CuO). Name the salt produced.

  1. 1

    Step 1: Identify the reactants and reaction type. This is an acid (nitric acid) reacting with a base (copper(II) oxide). The general equation is Acid + Base → Salt + Water.

  2. 2

    Step 2: Determine the products. The salt will be formed from the metal cation (Cu²⁺) and the acid anion (NO₃⁻). The salt is copper(II) nitrate, Cu(NO₃)₂. The other product is water (H₂O).

  3. 3

    Step 3: Write the unbalanced equation: HNO₃ + CuO → Cu(NO₃)₂ + H₂O.

  4. 4

    Step 4: Balance the equation. There are two nitrate ions on the right, so we need 2HNO₃ on the left. This gives two H atoms on the left, which balances with the H₂O on the right. The final balanced equation is 2HNO₃(aq) + CuO(s) → Cu(NO₃)₂(aq) + H₂O(l).

  5. 5

    Step 5: Name the salt. The salt produced is copper(II) nitrate.

Worked example 22 marks

A student adds dilute sulfuric acid to calcium carbonate. Describe the observations and name the gas produced.

  1. 1

    Step 1: Identify the reaction type. This is an acid reacting with a carbonate.

  2. 2

    Step 2: Recall the general equation: Acid + Carbonate → Salt + Water + Carbon Dioxide.

  3. 3

    Step 3: Identify the gas produced. The gas is carbon dioxide (CO₂).

  4. 4

    Step 4: Describe the observation. Carbon dioxide is a gas, so bubbling or fizzing (effervescence) will be observed. The solid calcium carbonate will also dissolve as it reacts to form soluble calcium sulfate (in this case, it's slightly soluble, but the reaction proceeds) and water.

Recap

  • Acids react with reactive metals to produce a salt and hydrogen gas.
  • Acids react with bases (like metal oxides and hydroxides) in a neutralisation reaction to form a salt and water.
  • Acids react with carbonates to produce a salt, water, and carbon dioxide gas.
  • The salt name is derived from the acid: chlorides from HCl, sulfates from H₂SO₄, nitrates from HNO₃.

Quick check

  1. What gas is produced when magnesium reacts with hydrochloric acid?1 mark
  2. Complete the word equation: Potassium hydroxide + Sulfuric acid → ?2 marks

3. Strong and Weak Acids and Alkalis

The strength of an acid or alkali is not the same as its concentration. Strength refers to the degree of ionisation (or dissociation) in water. A strong acid, like hydrochloric acid (HCl), fully ionises in water. Every HCl molecule splits into H⁺ and Cl⁻ ions. A weak acid, like ethanoic acid (CH₃COOH), only partially ionises. Only a small fraction of the molecules split into ions, so the solution contains mostly un-ionised molecules and a low concentration of H⁺ ions. This is shown with a reversible arrow: CH₃COOH(aq) ⇌ H⁺(aq) + CH₃COO⁻(aq). Similarly, a strong alkali like sodium hydroxide (NaOH) fully dissociates into Na⁺ and OH⁻ ions. A weak alkali like ammonia (NH₃) only reacts partially with water to form a low concentration of OH⁻ ions: NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq). Because strong acids/alkalis produce a higher concentration of mobile ions, their solutions have higher electrical conductivity and a more extreme pH (lower for acids, higher for alkalis) than weak acids/alkalis of the same molar concentration.

Strong Acid Example: HCl(aq) → H⁺(aq) + Cl⁻(aq)

Weak Acid Example: CH₃COOH(aq) ⇌ H⁺(aq) + CH₃COO⁻(aq)

Strong Alkali Example: NaOH(aq) → Na⁺(aq) + OH⁻(aq)

Weak Alkali Example: NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

Key term

Strong Acid: An acid that completely ionises in aqueous solution to produce a high concentration of hydrogen ions.

Examiner insight

Clearly state that the difference between strong and weak is the 'degree of ionisation' or 'extent of dissociation', not simply the 'amount of ions'.

Common pitfall

Confusing 'strong' with 'concentrated' and 'weak' with 'dilute'. A strong acid can be dilute (e.g., 0.01 mol/dm³ HCl), and a weak acid can be concentrated (e.g., 10 mol/dm³ CH₃COOH).

Worked example 14 marks

Two beakers contain 1.0 mol/dm³ hydrochloric acid and 1.0 mol/dm³ ethanoic acid respectively. Explain why the hydrochloric acid solution has a lower pH and a higher electrical conductivity.

  1. 1

    Step 1: Define strong and weak acids. Hydrochloric acid is a strong acid, meaning it fully ionises in water: HCl → H⁺ + Cl⁻.

  2. 2

    Step 2: Ethanoic acid is a weak acid, meaning it only partially ionises in water: CH₃COOH ⇌ H⁺ + CH₃COO⁻.

  3. 3

    Step 3: Relate ionisation to pH. Since HCl fully ionises, it produces a higher concentration of H⁺ ions than ethanoic acid at the same molar concentration. A higher concentration of H⁺ ions results in a lower pH value.

  4. 4

    Step 4: Relate ionisation to conductivity. Electrical conductivity in solutions depends on the concentration of mobile ions. Since the HCl solution has a higher concentration of total mobile ions (H⁺ and Cl⁻) than the ethanoic acid solution, it is a better conductor of electricity.

Recap

  • A strong acid or alkali is one that fully ionises in water.
  • A weak acid or alkali is one that only partially ionises in water.
  • Strength is about the degree of ionisation, while concentration is about the amount of substance per unit volume.
  • For the same concentration, strong acids have a lower pH and higher conductivity than weak acids.
  • For the same concentration, strong alkalis have a higher pH and higher conductivity than weak alkalis.

Quick check

  1. Is nitric acid (HNO₃) a strong or weak acid?1 mark
  2. Why is a reversible arrow (⇌) used for the ionisation of aqueous ammonia?1 mark

4. Classifying Oxides

Oxides are compounds containing oxygen and at least one other element. They can be classified into four types based on their acidic and basic properties.

  1. Basic Oxides: These are typically oxides of metals. They react with acids to form a salt and water. Most are insoluble (e.g., copper(II) oxide, CuO), but those of Group 1 and 2 metals are soluble and form alkaline solutions (e.g., sodium oxide, Na₂O).
  2. Acidic Oxides: These are typically oxides of non-metals. They react with bases/alkalis to form a salt and water. Examples include carbon dioxide (CO₂) and sulfur dioxide (SO₂).
  3. Amphoteric Oxides (Extended): These are special metal oxides that show both acidic and basic properties. They react with both acids and strong alkalis to form a salt and water. Common examples are zinc oxide (ZnO) and aluminium oxide (Al₂O₃). For example: ZnO + 2HCl → ZnCl₂ + H₂O (acting as a base) and ZnO + 2NaOH → Na₂ZnO₂ + H₂O (acting as an acid).
  4. Neutral Oxides (Extended): These are non-metal oxides that do not react with either acids or bases. Examples include carbon monoxide (CO), nitrogen(I) oxide (N₂O), and water (H₂O).

Basic Oxide + Acid → Salt + Water (e.g., MgO + 2HCl → MgCl₂ + H₂O)

Acidic Oxide + Base → Salt + Water (e.g., CO₂ + 2NaOH → Na₂CO₃ + H₂O)

Amphoteric Oxide + Acid → Salt + Water (e.g., Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O)

Amphoteric Oxide + Alkali → Salt + Water (e.g., Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O)

Key term

Amphoteric Oxide: An oxide that can act as both an acid and a base, reacting with both to form a salt and water.

Examiner insight

Be prepared to write equations for an amphoteric oxide (like zinc oxide) reacting with both a strong acid (like HCl) and a strong alkali (like NaOH).

Worked example 13 marks

Sulfur trioxide (SO₃) and magnesium oxide (MgO) are two different types of oxide.(a) Classify each oxide.(b) Write a balanced chemical equation for the reaction of magnesium oxide with sulfuric acid.

  1. 1

    (a) Sulfur is a non-metal, so sulfur trioxide (SO₃) is an acidic oxide. Magnesium is a metal, so magnesium oxide (MgO) is a basic oxide.

  2. 2

    (b) The reaction is between a basic oxide and an acid. The products will be a salt and water.

  3. 3

    The salt is formed from the magnesium ion (Mg²⁺) and the sulfate ion (SO₄²⁻), which is magnesium sulfate (MgSO₄).

  4. 4

    The word equation is: Magnesium oxide + Sulfuric acid → Magnesium sulfate + Water.

  5. 5

    The balanced chemical equation is: MgO(s) + H₂SO₄(aq) → MgSO₄(aq) + H₂O(l).

Recap

  • Basic oxides are metal oxides that react with acids.
  • Acidic oxides are non-metal oxides that react with bases.
  • Amphoteric oxides (e.g., ZnO, Al₂O₃) react with both acids and alkalis.
  • Neutral oxides (e.g., CO, H₂O) do not react with acids or bases.
  • Controlling soil acidity involves adding a base, like calcium oxide or calcium carbonate, to neutralise excess acid.

Quick check

  1. Is carbon dioxide (CO₂) an acidic, basic, amphoteric, or neutral oxide?1 mark
  2. Name an amphoteric oxide.1 mark

5. Neutralisation and Making Soluble Salts

Neutralisation is the reaction between an acid and a base to form a salt and water. The essential reaction involves hydrogen ions from the acid reacting with hydroxide ions from the alkali to form neutral water. The ionic equation for this is H⁺(aq) + OH⁻(aq) → H₂O(l). This principle is used to prepare soluble salts. There are two main methods. Method 1: Reacting an Acid with an Insoluble Solid. This is used for making salts from an acid and an insoluble metal, base, or carbonate. Step 1: Add the insoluble solid in excess (a little at a time) to a warm acid until no more reacts. This ensures all the acid is used up. Step 2: Filter the mixture to remove the unreacted excess solid. The filtrate is the salt solution. Step 3: Gently heat the filtrate to evaporate some of the water and form a saturated solution. Step 4: Leave the solution to cool, allowing crystals of the salt to form. Step 5: Filter off the crystals, wash them with a small amount of cold distilled water, and dry them. Method 2: Titration. This is used when both the acid and the base (an alkali) are soluble. Step 1: Use a pipette to measure a known volume of alkali into a conical flask and add a few drops of indicator. Step 2: Add acid from a burette, swirling the flask, until the indicator just changes colour (the end point). Record the volume of acid added. Step 3: Repeat the experiment using the exact same volumes of acid and alkali but without the indicator to get a pure salt solution. Step 4: Crystallise the salt from the pure solution as described in Method 1.

General Equation: Acid + Base → Salt + Water

Ionic Equation for Neutralisation: H⁺(aq) + OH⁻(aq) → H₂O(l)

Key term

Neutralisation: A chemical reaction in which an acid and a base react together to form a salt and water, with the resulting solution being neutral (pH 7).

Examiner insight

When describing salt preparation, examiners look for a clear, logical sequence of practical steps. Mentioning specific apparatus (beaker, filter funnel, evaporating basin) and the reasons for steps (e.g., 'add in excess to ensure all acid reacts') gains marks.

Worked example 16 marks

Describe a method to prepare a pure, dry sample of copper(II) sulfate crystals starting from solid copper(II) carbonate and dilute sulfuric acid.

  1. 1

    Step 1 (React): Gently warm the dilute sulfuric acid in a beaker. Add copper(II) carbonate powder in small amounts, stirring, until no more effervescence is seen and some unreacted solid remains at the bottom. This is adding in excess.

  2. 2

    Step 2 (Filter): Filter the mixture to remove the excess, unreacted copper(II) carbonate. The filtrate is a pure solution of copper(II) sulfate.

  3. 3

    Step 3 (Evaporate): Pour the filtrate into an evaporating basin and gently heat it to evaporate about half of the water, until the point of crystallisation is reached (test by dipping a cold glass rod into the solution to see if crystals form on it).

  4. 4

    Step 4 (Crystallise): Leave the saturated solution to cool slowly at room temperature. Blue crystals of copper(II) sulfate will form.

  5. 5

    Step 5 (Wash & Dry): Filter the crystals from the solution, wash them with a small amount of cold distilled water to remove any soluble impurities, and then dry them between sheets of filter paper or in a warm oven.

Recap

  • Neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water.
  • To make a soluble salt from an insoluble reactant, use the 'excess solid' method followed by filtration and crystallisation.
  • To make a soluble salt from a soluble base (alkali), use titration to find the correct volumes, then repeat without indicator and crystallise.
  • The key steps for obtaining crystals are: react, filter (if needed), evaporate, cool, wash, and dry.
  • An indicator is essential for a titration to identify the neutralisation point.

Quick check

  1. Which laboratory apparatus is used to accurately measure 25.0 cm³ of alkali into a conical flask?1 mark
  2. Why is the insoluble reactant added in excess when making a soluble salt?1 mark

6. Making Insoluble Salts by Precipitation

Insoluble salts cannot be made by crystallisation because they do not stay dissolved. Instead, they are made by a precipitation reaction. This involves mixing two different soluble salt solutions. One solution provides the required positive ion (cation) and the other provides the required negative ion (anion). When the two solutions are mixed, the cation and anion combine to form the insoluble salt, which appears as a solid precipitate. The other ions remain dissolved in the solution; these are called spectator ions because they do not take part in the reaction. The method is simple:

  1. Mix the two chosen soluble salt solutions.
  2. Filter the mixture to separate the solid precipitate from the solution.
  3. Wash the precipitate on the filter paper with distilled water to remove any soluble impurities.
  4. Dry the precipitate in a warm oven or by leaving it in a warm place.

General Reaction: Soluble Salt A(aq) + Soluble Salt B(aq) → Insoluble Salt C(s) + Soluble Salt D(aq)

Example: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Ionic Equation for Example: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

Key term

Precipitation: The formation of an insoluble solid (a precipitate) when two soluble substances react together in solution.

Examiner insight

You must be able to identify the spectator ions in a precipitation reaction; they are the ions that do not change state and are not part of the final ionic equation for the formation of the precipitate.

Common pitfall

Choosing starting reactants that are not soluble. You must know your salt solubility rules, for example, all nitrates are soluble, and all sodium/potassium salts are soluble.

Worked example 15 marks

Barium sulfate (BaSO₄) is an insoluble salt used in 'barium meals' for medical imaging.(a) Name two soluble compounds that could be reacted to prepare barium sulfate.(b) Write the full balanced equation and the ionic equation for the reaction.(c) Identify the spectator ions.

  1. 1

    (a) To make barium sulfate (BaSO₄), we need a soluble salt containing Ba²⁺ ions and a soluble salt containing SO₄²⁻ ions. A suitable pair would be barium chloride (BaCl₂) or barium nitrate (Ba(NO₃)₂) and sodium sulfate (Na₂SO₄) or sulfuric acid (H₂SO₄). Let's choose barium chloride and sodium sulfate.

  2. 2

    (b) Full balanced equation: BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq).

  3. 3

    Ionic equation: The ions involved are Ba²⁺(aq), 2Cl⁻(aq), 2Na⁺(aq), and SO₄²⁻(aq). The precipitate is BaSO₄(s). The ionic equation shows only the species that react: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s).

  4. 4

    (c) The spectator ions are the ones that do not appear in the ionic equation. They remain in solution. In this case, they are the sodium ions (Na⁺) and the chloride ions (Cl⁻).

Recap

  • Insoluble salts are prepared by precipitation reactions.
  • A precipitation reaction involves mixing two soluble salt solutions.
  • The solid formed in the reaction is called the precipitate.
  • The method involves mixing, filtering, washing, and drying the precipitate.
  • Spectator ions are ions that are present in the solution but do not take part in the reaction.

Quick check

  1. Name a soluble lead salt and a soluble chloride salt you could mix to make insoluble lead(II) chloride.2 marks
  2. What is the name of the solid formed in a precipitation reaction?1 mark

7. Quantitative Analysis: Titration Calculations

Titration is a precise experimental technique used to determine the unknown concentration of a solution (the analyte) by reacting it with a solution of known concentration (the standard solution). The key is to find the exact volume of the standard solution needed to completely neutralise the analyte. This is called the equivalence point, which is observed using an indicator. The calculation involves three main steps:

  1. Write a balanced chemical equation for the reaction to find the mole ratio (n) of acid to alkali.
  2. Calculate the moles of the solution with the known concentration and volume using the formula: Moles = Concentration × Volume (in dm³). Remember to convert volumes in cm³ to dm³ by dividing by 1000.
  3. Use the mole ratio from the balanced equation to determine the moles of the unknown solution. Then, calculate its concentration using the formula: Concentration = Moles / Volume (in dm³). Alternatively, the combined formula C₁V₁/n₁ = C₂V₂/n₂ can be used, where C is concentration, V is volume, and n is the mole ratio for substance 1 (acid) and substance 2 (alkali).

Concentration (mol/dm³) = Moles (mol) / Volume (dm³)

Volume (dm³) = Volume (cm³) / 1000

C₁V₁/n₁ = C₂V₂/n₂ (where C=concentration, V=volume, n=mole ratio)

Key term

Titration: A quantitative chemical analysis method used to determine the concentration of a solution by reacting it with a standard solution of known concentration.

Examiner insight

Examiners require all steps to be shown in calculation questions, including the balanced chemical equation, the formula used, correct substitution of values, and the final answer with units (mol/dm³).

Common pitfall

Forgetting to balance the chemical equation to find the correct mole ratio (n₁ and n₂), or using an incorrect ratio like 1:1 by default.

Worked example 14 marks

In a titration, 25.0 cm³ of 0.200 mol/dm³ sodium hydroxide (NaOH) solution was exactly neutralised by 20.0 cm³ of sulfuric acid (H₂SO₄). Calculate the concentration of the sulfuric acid in mol/dm³.

  1. 1

    Step 1: Write the balanced equation to find the mole ratio.

  2. 2

    2NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2H₂O(l)

  3. 3

    The mole ratio of NaOH : H₂SO₄ is 2 : 1.

  4. 4

    Step 2: Calculate the moles of the known substance (NaOH).

  5. 5

    Volume of NaOH = 25.0 cm³ = 0.0250 dm³.

  6. 6

    Moles of NaOH = Concentration × Volume = 0.200 mol/dm³ × 0.0250 dm³ = 0.00500 mol.

  7. 7

    Step 3: Use the mole ratio to find the moles of the unknown substance (H₂SO₄).

  8. 8

    Ratio NaOH : H₂SO₄ is 2 : 1. So, moles of H₂SO₄ = Moles of NaOH / 2.

  9. 9

    Moles of H₂SO₄ = 0.00500 mol / 2 = 0.00250 mol.

  10. 10

    Step 4: Calculate the concentration of the unknown substance (H₂SO₄).

  11. 11

    Volume of H₂SO₄ = 20.0 cm³ = 0.0200 dm³.

  12. 12

    Concentration of H₂SO₄ = Moles / Volume = 0.00250 mol / 0.0200 dm³ = 0.125 mol/dm³.

Recap

  • Titration is used to find the unknown concentration of a solution.
  • The mole ratio from the balanced chemical equation is essential for the calculation.
  • Always convert volumes from cm³ to dm³ for mole calculations (divide by 1000).
  • The formula C₁V₁/n₁ = C₂V₂/n₂ combines all steps into one calculation.
  • Show all your working steps clearly, including the balanced equation.

Quick check

  1. How many moles are in 50 cm³ of a 0.5 mol/dm³ solution?2 marks
  2. What is the mole ratio of acid to alkali in the reaction: 2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Name the salt produced in the reaction between (a) hydrochloric acid and potassium hydroxide, and (b) nitric acid and zinc carbonate.2 marks
  2. A student has two solutions of the same concentration: 0.1 mol/dm³ sulfuric acid (H₂SO₄) and 0.1 mol/dm³ ethanoic acid (CH₃COOH). Explain which solution would have a lower pH and why.3 marks
  3. Write a balanced chemical equation, including state symbols, for the reaction between aqueous sodium hydroxide and dilute sulfuric acid.3 marks
  4. Describe, step-by-step, how you would prepare a pure, dry sample of magnesium sulfate crystals starting from solid magnesium oxide and a dilute acid.5 marks
  5. Aluminium oxide (Al₂O₃) is amphoteric. Write two separate balanced chemical equations to show it reacting with (a) hydrochloric acid (HCl) and (b) hot, concentrated sodium hydroxide (NaOH).4 marks
  6. A farmer finds their soil is too acidic for growing crops. Name a type of chemical substance they could add to the soil to solve this problem and explain why it works.2 marks
  7. Lead(II) nitrate solution is mixed with potassium iodide solution to form a precipitate of lead(II) iodide. Write the ionic equation for this reaction and identify the spectator ions.3 marks
  8. A strong base, such as sodium hydroxide, is warmed with an ammonium salt, such as ammonium chloride. Name the gas produced and describe its characteristic smell and its effect on damp red litmus paper.3 marks
  9. 25.0 cm³ of a 0.150 mol/dm³ solution of potassium hydroxide (KOH) is required to neutralise 30.0 cm³ of a solution of phosphoric acid (H₃PO₄). The equation is: 3KOH + H₃PO₄ → K₃PO₄ + 3H₂O. Calculate the concentration of the phosphoric acid solution in mol/dm³.4 marks
  10. Distinguish between a 'strong acid' and a 'concentrated acid' using hydrochloric acid as an example.2 marks

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