Skip to content
Cambridge IGCSE0607

Magnitude of a vector

International Mathematics 0607 Chapter Notes

What this chapter covers

Magnitude of a vector
ShareWhatsAppPost
Magnitude of a vector notes

Read online free. Download a watermarked copy with a free account.

Read the notes

The full Magnitude of a vector notes as text: skim, search, and jump between subtopics.

~4 min read

1. The magnitude of a vector

The magnitude of a vector is its length. It is written with modulus signs: |a| is the magnitude of a and |overrightarrowAB| is the magnitude of overrightarrowAB.

The answer is a single number, not a vector. The vector beginpmatrixx yendpmatrix and its two components form a right-angled triangle, so Pythagoras gives the length.

The magnitude of (x,y) is the square root of (x² + y²).

|beginpmatrixx yendpmatrix| = √(x² + y²)

Examiner insight

“The magnitude of a vector notation was not always recognised and additions of column vectors or additions of components were often seen.” “A number of candidates were not familiar with the term ‘magnitude’ of a vector with some omitting the question and others adding the components.”

Worked example 12 marks

P is the point (3, 7) and Q is the point (7, 4). overrightarrowPQ = beginpmatrix4 -3endpmatrix. Work out |overrightarrowPQ|.

  1. 1

    |overrightarrowPQ| = √(4² + (-3)²) [1]

  2. 2

    = √(16 + 9) = √25 = 5 [1]

2. Negative components and surds

A negative component is squared like any other: (-5)² = 25. Square it in brackets, because -5² means -25.

The magnitude is a length, so it is one positive number. An answer of ± 5 does not earn full marks.

On a non-calculator paper, leave the answer exact. If x² + y² is not a square number, give a surd and simplify it by taking out the largest square factor.

(-5)² = 25

√52 = √(4 × 13) = 2√13

Examiner insight

“On several responses candidates omitted the brackets when squaring – 5 which was often, but not always, recovered in the next line of working.” “There were a few answers of ±5 which only gained one mark.”

Worked example 13 marks

Do not use a calculator. Work out |beginpmatrix-12 8endpmatrix|. Give your answer as a surd in its simplest form.

  1. 1

    √((-12)² + 8²) [1]

  2. 2

    = √(144 + 64) = √(208) [1]

  3. 3

    = √(16 × 13) = 4√13 [1]

3. Two points and calculator papers

The vector from one point to another is (end point) − (start point). Take care with the signs: examiners report many sign errors in the components of overrightarrowAB.

On a calculator paper, enter the square root of the sum of the squares, with the whole sum inside the root. Round only the final answer, to the accuracy asked for.

Examiners credit the answer "to the required degree of accuracy or in surd form". An inaccurate final answer scores no marks.

Examiner insight

“Many good solutions were seen with the correct final answer given to the required degree of accuracy or in surd form.”

Worked example 13 marks

A is the point (2, −3) and B is the point (−3, 1). Use a calculator to work out |overrightarrowAB|. Give your answer correct to 3 significant figures.

  1. 1

    overrightarrowAB = beginpmatrix-3-2 1-(-3)endpmatrix = beginpmatrix-5 4endpmatrix [1]

  2. 2

    |overrightarrowAB| = √((-5)² + 4²) = √41 [1]

  3. 3

    = 6.40 to 3 significant figures [1]

Recap

  • |a| and |overrightarrowAB| are the magnitude (length) of a vector. The answer is a number.
  • Magnitude of (x, y) = square root of (x² + y²).
  • Square a negative component in brackets.
  • Non-calculator: leave a surd, simplified. Calculator: round only the final answer.
  • Vector between two points = end point − start point.

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Do not use a calculator. Work out |beginpmatrix6 8endpmatrix|.2 marks
  2. Do not use a calculator. p = beginpmatrix-5 12endpmatrix. Work out |p|.2 marks
  3. Do not use a calculator. Work out |beginpmatrix-7 -24endpmatrix|.2 marks
  4. Do not use a calculator. A is the point (-1, 3) and B is the point (2, -1). Work out |overrightarrowAB|.3 marks
  5. Use a calculator to work out |beginpmatrix2 -5endpmatrix|. Give your answer correct to 3 significant figures.2 marks
  6. Do not use a calculator. Work out |beginpmatrix4 -6endpmatrix|. Give your answer in the form a√b, where b is as small as possible.3 marks
  7. Do not use a calculator. The vector beginpmatrixk 12endpmatrix has magnitude 13, and k is positive. Find k.3 marks
  8. Do not use a calculator. The vector beginpmatrixx 2xendpmatrix has magnitude √20. Find the possible values of x.3 marks
  9. Do not use a calculator. On a grid marked in metres, a drone flies in a straight line from P(-2, 5) to Q(4, -3), then in a straight line from Q to R(9, 9). (a) Work out the total distance the drone flies. (b) The drone then flies straight from R back to P. Work out this distance. Give your answer as a surd.6 marks
  10. Positions are measured in km from a radio mast at (0, 0). A helicopter is at (-4.6, 2.3) at 09 00 and at (3.1, -7.4) at 09 15. It flies in a straight line at a constant speed. Use a calculator. (a) Work out the distance the helicopter flies, correct to 3 significant figures. (b) Work out its speed in km / h, correct to 3 significant figures. (c) The mast's signal reaches 8 km. Decide whether the helicopter is in range at 09 15. Show your working.7 marks

Free notes are just the start.

Unlock every Workbook and Chapter at a Glance, and generate your own worksheets and predicted papers.

Explore plans

Related chapters