Cambridge AS & A Level9702

Astronomy and cosmology

Physics 9702 Chapter Notes

What this chapter covers

Astronomy and cosmology - Standard candlesAstronomy and cosmology - Stellar radiiAstronomy and cosmology - Hubble’s law and the Big Bang theory
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1. Luminosity, Flux & Standard Candles

The luminosity (L) of a star is the total radiant power it emits into space. Think of it as the star's intrinsic brightness, measured in Watts (W). It's a fundamental property of the star itself. However, what we observe from Earth is not its luminosity, but its radiant flux intensity (F). Radiant flux intensity is the radiant power received per unit area at a certain distance from the star, measured in Watts per square metre (W m^-2). As light spreads out from a star, its intensity decreases with distance. This relationship follows an inverse square law: the radiant flux intensity is inversely proportional to the square of the distance(d) from the star. This means that if you double the distance, the intensity becomes one-quarter. The formula connecting these quantities is F = L / (4πd^2), where 4πd^2 represents the surface area of a sphere at distance d from the star. Objects with a known luminosity are incredibly useful in astronomy and are called standard candles. By measuring their radiant flux intensity and knowing their luminosity, astronomers can calculate their distance from Earth using the inverse square law, allowing us to map out the vastness of the universe.

F = L / (4πd^2)

L = 4πd^2F

Key term

Standard Candle: An astronomical object of known luminosity, used to determine distances to galaxies.

Examiner insight

Examiners look for a clear understanding of the inverse square law and the ability to apply it correctly in calculations, as well as a precise definition of a standard candle and its purpose.

Common pitfall

Students often confuse luminosity with radiant flux intensity. Remember, luminosity is an intrinsic property of the star, while radiant flux intensity is what we measure and depends on both luminosity and distance.

Worked example 13 marks

A star has a luminosity of 3.8 x 10^26 W. An observer on Earth measures its radiant flux intensity to be 1.5 x 10^-9 W m^-2. Calculate the distance of the star from Earth.

  1. 1

    Rearrange the radiant flux intensity formula to solve for distance: F = L / (4πd^2) => d^2 = L / (4πF) => d = sqrt(L / (4πF)).

  2. 2

    Substitute the given values: d = sqrt(3.8 x 10^26 W / (4π x 1.5 x 10^-9 W m^-2)).

  3. 3

    Calculate the value: d = sqrt(3.8 x 10^26 / (1.88495 x 10^-8)) = sqrt(2.0169 x 10^34) = 1.42 x 10^17 m.

Worked example 23 marks

A Cepheid variable star, a type of standard candle, is known to have a luminosity of 5.0 x 10^30 W. If it is located 1.0 x 10^19 m away from Earth, what radiant flux intensity would an observer on Earth measure?

  1. 1

    Use the formula for radiant flux intensity: F = L / (4πd^2).

  2. 2

    Substitute the given values: F = 5.0 x 10^30 W / (4π x (1.0 x 10^19 m)^2).

  3. 3

    Calculate the value: F = 5.0 x 10^30 / (4π x 1.0 x 10^38) = 5.0 x 10^30 / (1.2566 x 10^39) = 3.98 x 10^-9 W m^-2.

Recap

  • Luminosity (L) is the total power emitted by a star (W).
  • Radiant flux intensity (F) is the power received per unit area (W m^-2).
  • F decreases with the square of the distance: F = L / (4πd^2).
  • Standard candles are objects with known luminosity, vital for measuring cosmic distances.

Quick check

  1. What is the unit of luminosity?1 mark
  2. If the distance to a star doubles, how does the radiant flux intensity change?1 mark

2. Stellar Temperature & Size

The properties of stars, such as their surface temperature and radius, are closely linked to their emitted radiation. Two key laws help us understand these relationships: Wien's Displacement Law and the Stefan-Boltzmann Law. Wien's Displacement Law describes the relationship between a star's surface temperature (T) and the peak wavelength (λ_max) of its emitted radiation. Hotter stars emit more radiation at shorter wavelengths, appearing bluer, while cooler stars emit more at longer wavelengths, appearing redder. The law states that λ_max T = constant (approximately 2.898 x 10^-3 m K). This means if you know the peak wavelength of a star's spectrum, you can estimate its surface temperature. The Stefan-Boltzmann Law relates a star's total luminosity (L) to its surface temperature (T) and radius (r). It states that L = 4πσr^2T^4, where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W m^-2 K^-4). This law tells us that a larger or hotter star will be more luminous. By combining these two laws, astronomers can estimate the radius of a star if its luminosity and surface temperature are known.

λ_max T = constant

L = 4πσr^2T^4

Key term

Wien's Displacement Law: A law stating that the peak wavelength of emitted radiation from a black body is inversely proportional to its absolute temperature.

Examiner insight

For Wien's Law, examiners expect correct unit conversion and an understanding of the inverse relationship. For Stefan-Boltzmann, accuracy in handling exponents and the constant is key. Showing clear rearrangement of formulas is also important.

Common pitfall

A common mistake is forgetting to convert wavelength units (e.g., nm to m) or to use absolute temperature (Kelvin) in calculations for both Wien's and Stefan-Boltzmann laws. Also, be careful with powers of 10 when dealing with T^4.

Worked example 13 marks

The peak wavelength of radiation emitted by a star is measured to be 480 nm. Estimate the surface temperature of this star. (Wien's constant = 2.898 x 10^-3 m K)

  1. 1

    Convert the peak wavelength to metres: λ_max = 480 nm = 480 x 10^-9 m.

  2. 2

    Use Wien's Displacement Law: λ_max T = constant.

  3. 3

    Rearrange to find T: T = constant / λ_max.

  4. 4

    Substitute values: T = 2.898 x 10^-3 m K / (480 x 10^-9 m).

  5. 5

    Calculate: T = 6037.5 K (approximately 6040 K to 3 significant figures).

Worked example 24 marks

A white dwarf star has a surface temperature of 10,000 K and a luminosity of 1.0 x 10^25 W. Calculate its radius. (Stefan-Boltzmann constant σ = 5.67 x 10^-8 W m^-2 K^-4)

  1. 1

    Use the Stefan-Boltzmann Law: L = 4πσr^2T^4.

  2. 2

    Rearrange to solve for r: r^2 = L / (4πσT^4) => r = sqrt(L / (4πσT^4)).

  3. 3

    Substitute the given values: r = sqrt(1.0 x 10^25 W / (4π x 5.67 x 10^-8 W m^-2 K^-4 x (10000 K)^4)).

  4. 4

    Calculate the denominator: 4π x 5.67 x 10^-8 x (10^4)^4 = 4π x 5.67 x 10^-8 x 10^16 = 4π x 5.67 x 10^8 = 7.122 x 10^9.

  5. 5

    Calculate r: r = sqrt(1.0 x 10^25 / 7.122 x 10^9) = sqrt(1.404 x 10^15) = 3.75 x 10^7 m.

Recap

  • Wien's Law (λ_max T = constant) relates peak wavelength to surface temperature.
  • Hotter stars emit shorter wavelengths (bluer light).
  • Stefan-Boltzmann Law (L = 4πσr^2T^4) relates luminosity, radius, and temperature.
  • A star's radius can be estimated using its luminosity and temperature.

Quick check

  1. What happens to the peak wavelength of radiation emitted by a star if its surface temperature increases?1 mark
  2. Which physical quantity does the Stefan-Boltzmann constant relate to?1 mark

3. Cosmic Expansion & Redshift

Observations of distant galaxies reveal a phenomenon called redshift. This means that the spectral lines (specific wavelengths of light emitted or absorbed by elements) from these galaxies are shifted towards the red end of the electromagnetic spectrum, indicating an increase in their observed wavelength (Δλ). This redshift is analogous to the Doppler effect for sound waves: just as a receding ambulance siren sounds lower in pitch, light from a receding source has its wavelength stretched. The Doppler redshift equation quantifies this: Δλ/λ ≈ Δf/f ≈ v/c, where λ is the original wavelength, Δλ is the change in wavelength, f is the original frequency, Δf is the change in frequency, v is the recession speed of the source, and c is the speed of light in a vacuum. The observation that almost all distant galaxies show redshift implies that they are moving away from us. Furthermore, the amount of redshift is proportional to the distance of the galaxy. This leads to Hubble's Law, which states that the recession speed(v) of a galaxy is directly proportional to its distance(d) from us: v = H_0d, where H_0 is the Hubble constant. This law is fundamental evidence for the Big Bang theory, which posits that the universe originated from an extremely hot, dense state and has been expanding ever since. The redshift of galaxies is not them moving through space, but rather the expansion of space itself, stretching the wavelengths of light as it travels.

Δλ/λ ≈ Δf/f ≈ v/c

v = H_0d

Key term

Redshift: The increase in wavelength of electromagnetic radiation from a receding source, indicating that the source is moving away from the observer.

Examiner insight

Examiners expect students to correctly apply the Doppler redshift formula and Hubble's Law. Crucially, they also look for an understanding that redshift implies an expanding universe, which supports the Big Bang theory.

Common pitfall

Students sometimes forget that the Doppler redshift equation uses the *change* in wavelength (Δλ), not the observed wavelength itself. Also, ensure consistent units (e.g., convert km/s to m/s if c is in m/s).

Worked example 14 marks

A spectral line of hydrogen normally has a wavelength of 656.3 nm. In the spectrum of a distant galaxy, this line is observed at 668.0 nm. Calculate the recession speed of this galaxy.

  1. 1

    Identify the original wavelength (λ) and the observed wavelength (λ_observed). Calculate the change in wavelength (Δλ): Δλ = λ_observed - λ = 668.0 nm - 656.3 nm = 11.7 nm.

  2. 2

    Use the Doppler redshift equation: Δλ/λ = v/c.

  3. 3

    Rearrange to solve for v: v = (Δλ/λ) x c.

  4. 4

    Substitute values (using c = 3.00 x 10^8 m s^-1): v = (11.7 nm / 656.3 nm) x (3.00 x 10^8 m s^-1). Note that nm units cancel out.

  5. 5

    Calculate: v = (0.017827) x (3.00 x 10^8) = 5.35 x 10^6 m s^-1.

Worked example 23 marks

A galaxy is observed to be receding at a speed of 2.1 x 10^7 m s^-1. If the Hubble constant H_0 is 2.2 x 10^-18 s^-1, estimate the distance to this galaxy.

  1. 1

    Use Hubble's Law: v = H_0d.

  2. 2

    Rearrange to solve for d: d = v / H_0.

  3. 3

    Substitute the given values: d = 2.1 x 10^7 m s^-1 / (2.2 x 10^-18 s^-1).

  4. 4

    Calculate: d = 9.55 x 10^24 m.

Recap

  • Redshift is the stretching of light wavelengths from receding objects.
  • The Doppler redshift equation (Δλ/λ = v/c) relates redshift to recession speed.
  • Hubble's Law (v = H_0d) states that recession speed is proportional to distance.
  • Redshift and Hubble's Law provide strong evidence for the Big Bang and an expanding universe.

Quick check

  1. What does a 'redshifted' spectral line indicate about a galaxy's motion?1 mark
  2. State Hubble's Law in words.1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Define luminosity and state its SI unit.2 marks
  2. Explain what a 'standard candle' is and how it is used in astronomy.3 marks
  3. A star has a luminosity of 7.6 x 10^27 W. An observer on a planet 5.0 x 10^17 m away from the star measures its radiant flux intensity. Calculate this intensity.3 marks
  4. The peak wavelength of radiation emitted by a star is 650 nm. Calculate its surface temperature. (Wien's constant = 2.898 x 10^-3 m K)3 marks
  5. Explain how the Stefan-Boltzmann law can be used alongside Wien's displacement law to estimate the radius of a star.4 marks
  6. A star has a surface temperature of 7500 K and a radius of 3.0 x 10^9 m. Calculate its luminosity. (Stefan-Boltzmann constant σ = 5.67 x 10^-8 W m^-2 K^-4)4 marks
  7. A specific spectral line of hydrogen has a laboratory wavelength of 486.1 nm. In the spectrum of a distant galaxy, this line is observed at 492.5 nm. Calculate the recession speed of this galaxy.4 marks
  8. State Hubble's Law and describe how it provides evidence for the Big Bang theory.4 marks
  9. A galaxy is observed to be moving away from Earth at a speed of 1.5 x 10^7 m s^-1. If the Hubble constant is 2.2 x 10^-18 s^-1, calculate the distance to this galaxy.3 marks
  10. A red giant star has a significantly lower surface temperature than the Sun but can have a much greater luminosity. Explain how this is possible, referring to the relevant physical law.3 marks

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