1. Luminosity, Flux & Standard Candles
The luminosity (L) of a star is the total radiant power it emits into space. Think of it as the star's intrinsic brightness, measured in Watts (W). It's a fundamental property of the star itself. However, what we observe from Earth is not its luminosity, but its radiant flux intensity (F). Radiant flux intensity is the radiant power received per unit area at a certain distance from the star, measured in Watts per square metre (W m^-2). As light spreads out from a star, its intensity decreases with distance. This relationship follows an inverse square law: the radiant flux intensity is inversely proportional to the square of the distance(d) from the star. This means that if you double the distance, the intensity becomes one-quarter. The formula connecting these quantities is F = L / (4πd^2), where 4πd^2 represents the surface area of a sphere at distance d from the star. Objects with a known luminosity are incredibly useful in astronomy and are called standard candles. By measuring their radiant flux intensity and knowing their luminosity, astronomers can calculate their distance from Earth using the inverse square law, allowing us to map out the vastness of the universe.
F = L / (4πd^2)
L = 4πd^2F
Key term
Examiner insight
Common pitfall
Worked example 13 marks
A star has a luminosity of 3.8 x 10^26 W. An observer on Earth measures its radiant flux intensity to be 1.5 x 10^-9 W m^-2. Calculate the distance of the star from Earth.
- 1
Rearrange the radiant flux intensity formula to solve for distance: F = L / (4πd^2) => d^2 = L / (4πF) => d = sqrt(L / (4πF)).
- 2
Substitute the given values: d = sqrt(3.8 x 10^26 W / (4π x 1.5 x 10^-9 W m^-2)).
- 3
Calculate the value: d = sqrt(3.8 x 10^26 / (1.88495 x 10^-8)) = sqrt(2.0169 x 10^34) = 1.42 x 10^17 m.
Worked example 23 marks
A Cepheid variable star, a type of standard candle, is known to have a luminosity of 5.0 x 10^30 W. If it is located 1.0 x 10^19 m away from Earth, what radiant flux intensity would an observer on Earth measure?
- 1
Use the formula for radiant flux intensity: F = L / (4πd^2).
- 2
Substitute the given values: F = 5.0 x 10^30 W / (4π x (1.0 x 10^19 m)^2).
- 3
Calculate the value: F = 5.0 x 10^30 / (4π x 1.0 x 10^38) = 5.0 x 10^30 / (1.2566 x 10^39) = 3.98 x 10^-9 W m^-2.
Recap
- Luminosity (L) is the total power emitted by a star (W).
- Radiant flux intensity (F) is the power received per unit area (W m^-2).
- F decreases with the square of the distance: F = L / (4πd^2).
- Standard candles are objects with known luminosity, vital for measuring cosmic distances.
Quick check
- What is the unit of luminosity?1 mark
- If the distance to a star doubles, how does the radiant flux intensity change?1 mark