Cambridge AS & A Level9702

Oscillations

Physics 9702 Chapter Notes

What this chapter covers

Oscillations - Simple harmonic oscillationsOscillations - Energy in simple harmonic motionOscillations - Damped and forced oscillations, resonance
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1. The Language of Oscillations

An oscillation is a repetitive back-and-forth motion of an object around a central point, known as the equilibrium position. This is the position the object would rest at if it stopped moving. To describe these oscillations precisely, we use a few key terms. 'Displacement'(x) is the object's distance and direction from its equilibrium position at any instant. The maximum displacement is called the 'amplitude' (x₀). The 'period' (T) is the time it takes to complete one full oscillation (e.g., from one peak, through the trough, and back to the next peak). The 'frequency'(f) is the number of complete oscillations that occur every second. Frequency and period are inversely related: if the period is long, the frequency is low, and vice versa.

f = 1 / T

T = 1 / f

Key term

Amplitude (x₀): The maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position.

Examiner insight

When reading from a graph, always state the values you are using and be as precise as the graph allows. For amplitude and period, show that you are reading the maximum value or the time for a full cycle.

Common pitfall

Confusing period (time for one oscillation, in seconds) with frequency (oscillations per second, in Hertz). They are reciprocals, not the same thing.

Worked example 13 marks

The displacement-time graph shows the motion of a mass on a spring. Determine:(a) the amplitude,(b) the period, and(c) the frequency of the oscillation.

  1. 1

    (a) The amplitude is the maximum displacement from the equilibrium position (x=0). From the graph, the peak displacement is 5.0 cm. So, amplitude x₀ = 5.0 cm or 0.050 m.

  2. 2

    (b) The period is the time for one complete oscillation. The graph shows one full cycle is completed at t = 4.0 s. So, period T = 4.0 s.

  3. 3

    (c) Frequency is the reciprocal of the period. Using f = 1/T. f = 1 / 4.0 s = 0.25 Hz.

Recap

  • An oscillation is a repeated motion about an equilibrium position.
  • Amplitude is the maximum displacement from the equilibrium position.
  • Period (T) is the time taken for one complete oscillation.
  • Frequency (f) is the number of oscillations per second.
  • Frequency and period are related by the equation f = 1/T.

Quick check

  1. An object completes 20 oscillations in 10 seconds. What is its frequency and period?2 marks

2. Defining Simple Harmonic Motion (SHM)

Simple Harmonic Motion (SHM) is a special, very common type of oscillation. For an object to be moving with SHM, its motion must satisfy two specific conditions: 1. Its acceleration is directly proportional to its displacement from the equilibrium position. 2. Its acceleration is always directed towards the equilibrium position. This means that the further the object is from the centre, the stronger the force pulling it back, and therefore the greater its acceleration towards the centre. We can summarise these two conditions in a single, powerful equation: a = -ω²x. Here, 'a' is acceleration, 'x' is displacement, and 'ω' (omega) is a constant called the angular frequency. The negative sign is crucial – it mathematically shows that the acceleration 'a' is always in the opposite direction to the displacement 'x'.

a = -ω²x

Key term

Simple Harmonic Motion (SHM): Motion where the acceleration of an object is directly proportional to its displacement from an equilibrium position and is always directed towards that equilibrium position.

Examiner insight

Examiners expect you to state both conditions for SHM (proportionality and direction) for full marks in a definition question. Simply writing the equation a = -ω²x is often not enough without explanation.

Common pitfall

Forgetting the negative sign when writing the defining equation for SHM, or failing to mention the direction of acceleration in the definition.

Worked example 14 marks

An object oscillates such that its acceleration 'a' is given by the equation a = -36x, where 'x' is its displacement from a fixed point.(a) Explain why the motion is simple harmonic.(b) Determine the period of the oscillation.

  1. 1

    (a) The motion is SHM because the acceleration 'a' is directly proportional to the displacement 'x' (a ∝ -x). The negative sign indicates that the acceleration is always directed opposite to the displacement, i.e., towards the equilibrium position. This matches the definition of SHM.

  2. 2

    (b) First, compare the given equation (a = -36x) with the defining equation for SHM (a = -ω²x). By comparison, we can see that ω² = 36. Therefore, ω = √36 = 6.0 rad s⁻¹.

  3. 3

    Now, we use the relationship between angular frequency ω and period T: T = 2π / ω. T = 2π / 6.0 = 1.05 s (to 3 s.f.).

Recap

  • SHM is defined by the relationship a ∝ -x.
  • The acceleration is always directed towards the equilibrium position.
  • The defining equation for SHM is a = -ω²x.
  • The negative sign in the equation is essential as it indicates the direction of acceleration.

Quick check

  1. What are the two conditions for an object's motion to be considered simple harmonic?2 marks

3. The Mathematics of SHM

The defining equation of SHM, a = -ω²x, is a differential equation whose solutions describe the object's position and velocity over time. The displacement 'x' at time 't' can be described by a sine or cosine function, depending on where the oscillation starts. If the object starts at the equilibrium position (x=0 at t=0), we use x = x₀sin(ωt). If it starts at the maximum displacement (x=x₀ at t=0), we use x = x₀cos(ωt). The angular frequency 'ω' is the key link between time and the oscillation's properties. It's related to frequency 'f' and period 'T' by ω = 2πf = 2π/T. The velocity 'v' also varies sinusoidally. The maximum speed, v₀, occurs at the equilibrium position (x=0) and is given by v₀ = ωx₀. At any other displacement 'x', the speed can be found using the useful equation v = ±ω√(x₀² - x²).

ω = 2πf

ω = 2π / T

x = x₀sin(ωt) (starts at equilibrium)

x = x₀cos(ωt) (starts at amplitude)

v₀ = ωx₀

v = ±ω√(x₀² - x²)

Key term

Angular Frequency (ω): A measure of oscillation rate in radians per second, related to frequency f by ω = 2πf, which determines how quickly the phase of the oscillation changes.

Common pitfall

Forgetting to set calculators to radians mode when using trigonometric functions with ωt. The 'angle' ωt is always in radians, not degrees.

Worked example 15 marks

A pendulum bob oscillates with SHM. Its period is 1.5 s and its amplitude is 4.0 cm. Calculate:(a) its angular frequency,(b) its maximum speed, and(c) its speed when it is 2.0 cm from the equilibrium position.

  1. 1

    (a) Use the formula relating angular frequency and period: ω = 2π / T. ω = 2π / 1.5 = 4.19 rad s⁻¹ (3 s.f.).

  2. 2

    (b) Maximum speed v₀ occurs at the centre and is given by v₀ = ωx₀. First, convert amplitude to metres: x₀ = 4.0 cm = 0.040 m. v₀ = 4.19 × 0.040 = 0.168 m s⁻¹ (3 s.f.).

  3. 3

    (c) Use the formula for speed at a given displacement: v = ±ω√(x₀² - x²). Convert displacement to metres: x = 2.0 cm = 0.020 m. v = ±4.19 × √(0.040² - 0.020²) = ±4.19 × √(0.0016 - 0.0004) = ±4.19 × √0.0012. v = ±0.145 m s⁻¹ (3 s.f.). The speed is 0.145 m s⁻¹.

Recap

  • Displacement in SHM is described by x = x₀sin(ωt) or x = x₀cos(ωt).
  • Angular frequency is calculated using ω = 2π/T or ω = 2πf.
  • Maximum speed is v₀ = ωx₀ and occurs at the equilibrium position.
  • Speed at any displacement x is given by v = ±ω√(x₀² - x²).
  • Remember to use radians for angles in SHM equations.

Quick check

  1. An oscillator has a frequency of 50 Hz. What is its angular frequency?1 mark
  2. At what point in an oscillation is the speed zero?1 mark

4. Energy Changes in SHM

During simple harmonic motion, there is a continuous exchange between kinetic energy (KE) and potential energy (PE). At the extreme points of the oscillation (x = ±x₀), the object is momentarily stationary, so its speed is zero and its KE is zero. Here, all the energy is stored as potential energy (e.g., elastic potential energy in a spring or gravitational potential energy in a pendulum). As the object moves towards the equilibrium position (x=0), this potential energy is converted into kinetic energy. At the equilibrium position, the speed is maximum (v = v₀), so KE is maximum, and the potential energy is zero (by definition). In an ideal, undamped system, no energy is lost. The total energy (E = KE + PE) remains constant throughout the oscillation. This total energy is determined by the mass (m), angular frequency (ω), and the square of the amplitude (x₀), given by the equation E = ½mω²x₀².

KE = ½mv²

PE = ½mω²x²

Total Energy E = KE + PE

Total Energy E = ½mω²x₀²

Key term

Total Energy (in SHM): The constant sum of the kinetic and potential energies of an ideal oscillator, which is proportional to the square of the amplitude.

Examiner insight

Sketches of energy vs. displacement are common questions. Ensure your KE graph is an 'n-shaped' parabola and your PE graph is a 'u-shaped' parabola, summing to a constant total energy represented by a horizontal line.

Worked example 14 marks

A 250 g mass is attached to a spring and oscillates with SHM. The frequency of oscillation is 2.0 Hz and the amplitude is 8.0 cm.(a) Calculate the total energy of the system.(b) What is the maximum kinetic energy of the mass?

  1. 1

    (a) First, find the angular frequency ω: ω = 2πf = 2π × 2.0 = 4π rad s⁻¹. Convert mass and amplitude to SI units: m = 250 g = 0.250 kg; x₀ = 8.0 cm = 0.080 m. Now use the total energy formula: E = ½mω²x₀². E = 0.5 × 0.250 × (4π)² × (0.080)². E = 0.125 × 157.9 × 0.0064 = 0.126 J (3 s.f.).

  2. 2

    (b) The total energy of the system is constant. The maximum kinetic energy occurs when the potential energy is zero (at x=0). At this point, KE_max = Total Energy. Therefore, the maximum kinetic energy is 0.126 J.

Recap

  • In SHM, energy continuously converts between kinetic and potential forms.
  • Kinetic energy is maximum at the equilibrium position (x=0).
  • Potential energy is maximum at the amplitude positions (x=±x₀).
  • For an undamped oscillator, total energy is constant.
  • Total energy is given by E = ½mω²x₀² and is proportional to the amplitude squared.

Quick check

  1. An oscillator's amplitude is tripled. By what factor does its total energy increase?1 mark

5. Damped Oscillations

In real-world systems, oscillations don't continue forever. Resistive forces, such as air resistance and internal friction, remove energy from the system, causing the amplitude to decrease over time. This effect is called damping. There are three main types of damping. 'Light damping' is where the amplitude decreases gradually over many oscillations, like a pendulum slowly coming to rest. 'Heavy damping' is where the system takes a long time to return to equilibrium without oscillating. 'Critical damping' is a special case where the system returns to its equilibrium position in the shortest possible time without overshooting or oscillating at all. Critical damping is highly desirable in systems like car suspension, where you want to absorb a bump quickly without the car bouncing up and down afterwards.

Key term

Critical Damping: The minimum amount of damping that allows an oscillating system to return to its equilibrium position in the shortest possible time without oscillating.

Fun fact

Doors with automatic closers use damping. A well-adjusted closer uses critical damping to shut the door quickly without slamming it.

Worked example 13 marks

A student displaces a mass on a spring and releases it. Sketch three displacement-time graphs on the same axes to show the motion of the mass for(a) light damping,(b) critical damping, and(c) heavy damping. Label each graph clearly.

  1. 1
    1. Draw the axes: Displacement (y-axis) against Time (x-axis). Mark the origin as the equilibrium position.
  2. 2
    1. (a) For light damping, draw a sinusoidal curve whose amplitude exponentially decreases with time. It should complete several oscillations before coming to rest.
  3. 3
    1. (b) For critical damping, draw a curve that starts at the initial displacement and returns to the equilibrium position (x=0) as quickly as possible without crossing it.
  4. 4
    1. (c) For heavy damping, draw a curve that also starts at the initial displacement and returns to equilibrium without oscillating, but takes longer to do so than the critically damped case.
  5. 5
    1. Label each of the three curves clearly as 'Light', 'Critical', and 'Heavy'.

Recap

  • Damping is the loss of energy from an oscillating system due to resistive forces.
  • Damping causes the amplitude of the oscillation to decrease over time.
  • Light damping involves a gradual decrease in amplitude over many cycles.
  • Critical damping returns the system to equilibrium in the minimum time without oscillation.
  • Heavy damping is a slow return to equilibrium with no oscillation.

Quick check

  1. What type of damping is used in a car's suspension system and why?2 marks

6. Forced Oscillations and Resonance

All oscillating systems have a 'natural frequency' (f₀), the frequency at which they will oscillate if disturbed and then left alone. When a periodic external force, called a driving force, is applied to an oscillator, it's called a 'forced oscillation'. The system is forced to oscillate at the 'driving frequency' of the external force. A remarkable phenomenon called 'resonance' occurs when the driving frequency is equal or very close to the system's natural frequency. At resonance, there is a very efficient transfer of energy from the driver to the oscillating system. This causes the amplitude of the oscillations to grow dramatically. Damping plays a key role: with less damping, the resonance peak is sharper and the maximum amplitude is much larger. Resonance can be destructive (like a bridge collapsing in high winds) or useful (like in microwave ovens, where microwaves at the natural frequency of water molecules heat food, or in tuning a radio).

Key term

Resonance: The phenomenon where the amplitude of a driven oscillation becomes very large when the driving frequency matches the natural frequency of the system.

Fun fact

The infamous collapse of the Tacoma Narrows Bridge in 1940 is a classic, albeit complex, example of aerodynamic effects causing large-amplitude oscillations that led to structural failure, often cited in the context of resonance.

Worked example 14 marks

A child is on a swing, which is a type of pendulum.(a) What is meant by the natural frequency of the swing?(b) To get the swing to go higher, an adult gives it a series of pushes. Explain how the timing of the pushes will determine the amplitude of the swing, referring to the concept of resonance.

  1. 1

    (a) The natural frequency of the swing is the frequency at which it would oscillate back and forth if the child were pulled back, released, and then left alone.

  2. 2

    (b) The adult's pushes provide a periodic driving force. If the adult pushes at a random frequency, the swing's motion will be erratic and the amplitude small. To make the swing go higher (increase its amplitude), the adult must time their pushes to match the swing's natural frequency. This is resonance.

  3. 3

    When the driving frequency (of the pushes) equals the natural frequency (of the swing), energy is transferred to the swing very efficiently on each push. This causes the amplitude of the swing to build up to a large value.

Recap

  • Natural frequency is the frequency at which a system oscillates without any external driving force.
  • A forced oscillation occurs when a periodic driving force is applied.
  • Resonance occurs when the driving frequency equals the natural frequency.
  • At resonance, amplitude grows to a maximum, limited only by damping.
  • Damping reduces the amplitude at resonance.

Quick check

  1. What is the condition for resonance to occur in a forced oscillation?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. A small object is oscillating with simple harmonic motion of period 0.60 s and amplitude 5.0 cm. Calculate the maximum speed of the object.3 marks
  2. State the two defining conditions for an object to be executing simple harmonic motion.2 marks
  3. A mass of 400 g oscillates with SHM. Its displacement x in metres is given by the equation x = 0.10 cos(8.0t). Determine (a) the amplitude, (b) the frequency, and (c) the total energy of the oscillation.5 marks
  4. Describe what is meant by damping in an oscillating system and explain the difference between light damping and critical damping. You may use sketches to illustrate your answer.4 marks
  5. A particle moves with SHM. Its acceleration 'a' is -144x, where x is the displacement in metres. What is the period of the motion?3 marks
  6. Explain the phenomenon of resonance. Give one example where resonance is useful and one example where it is a problem.4 marks
  7. An object of mass 0.50 kg performs SHM with an amplitude of 0.12 m and a period of 2.5 s. Calculate the speed of the object when its displacement from the equilibrium position is 0.080 m.4 marks
  8. A simple pendulum and a mass-spring system both have a period of 2.0 s on Earth. They are both taken to the Moon, where the acceleration of free fall is about 1/6th of that on Earth. Describe and explain what happens to the period of each oscillator.4 marks
  9. The total energy of a body executing SHM is E. What is the kinetic energy of the body when its displacement is half of its amplitude? Give your answer in terms of E.3 marks
  10. A graph shows the displacement x of an oscillator against time t. On a new set of axes, sketch the corresponding graph of acceleration a against time t for the same oscillator. Explain the relationship between the two graphs.3 marks

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