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Chemistry: Properties of materials

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Chemistry: Properties of materials
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1. Elements, Compounds, and Mixtures

All substances can be classified into three main groups. Elements are the simplest form of matter, made up of only one type of atom (e.g., oxygen, O₂; iron, Fe). Compounds are pure substances formed when two or more different elements are chemically bonded together in a fixed ratio. These bonds can only be broken by a chemical reaction (e.g., water, H₂O; carbon dioxide, CO₂). Mixtures consist of two or more elements or compounds that are not chemically bonded. Their components can be separated by physical means like filtering or evaporation (e.g., salt water, air).

Key term

Pure Substance: A substance consisting of only one type of element or one type of compound, with definite chemical and physical properties.

Examiner insight

Examiners frequently test the distinction between compounds and mixtures, so be ready to explain that mixtures can be separated by physical means while compounds require chemical reactions.

Common pitfall

Confusing a compound like water (H₂O) with a mixture of hydrogen and oxygen gas. The key difference is the chemical bond in the compound, which gives it entirely new properties.

Worked example 13 marks

Classify the following as an element, compound, or mixture:(a) Pure gold (Au),(b) Table salt (NaCl),(c) Air.

  1. 1

    (a) Pure gold (Au) is an element because it is made up of only one type of atom, gold atoms.

  2. 2

    (b) Table salt (NaCl) is a compound because it is formed from two different elements, sodium and chlorine, chemically bonded together in a fixed 1:1 ratio.

  3. 3

    (c) Air is a mixture because it consists of several different gases (like nitrogen, oxygen, argon) that are not chemically bonded together.

Recap

  • An element is a pure substance containing only one type of atom.
  • A compound is a pure substance containing two or more types of atoms chemically bonded together.
  • A mixture contains two or more substances that are not chemically bonded.
  • Mixtures can be separated by physical methods, but compounds cannot.
  • Both elements and compounds are classified as pure substances.

Quick check

  1. Is pure water (H₂O) an element, compound, or mixture? Explain why.2 marks

2. The Process of Dissolving

Dissolving is the process where a substance breaks down and mixes completely with another substance to form a solution. The substance that dissolves is called the solute (e.g., sugar). The substance that does the dissolving is called the solvent (e.g., water). The resulting mixture is called a solution. In a solution, the solute particles are spread evenly throughout the solvent particles, which is why most solutions are transparent (you can see through them). This is a physical change, not a chemical reaction, and the total mass is conserved, meaning the mass of the solution equals the mass of the solute plus the mass of the solvent.

Key term

Solution: A homogeneous mixture formed when a solute dissolves in a solvent.

Fun fact

While water is called the 'universal solvent' because it dissolves more substances than any other liquid, it cannot dissolve everything, like oils and fats.

Worked example 13 marks

When making a cup of instant coffee, coffee powder and sugar are stirred into hot water. Identify the solute(s), the solvent, and the solution.

  1. 1

    The substances that dissolve are the coffee powder and the sugar. Therefore, the solutes are coffee powder and sugar.

  2. 2

    The substance that does the dissolving is the hot water. Therefore, the solvent is water.

  3. 3

    The final mixture of dissolved coffee and sugar in water is the solution.

Recap

  • The solute is the substance that dissolves.
  • The solvent is the substance that does the dissolving.
  • A solution is a mixture of a solute dissolved in a solvent.
  • Dissolving is a physical change, and mass is conserved.
  • Solutions are transparent because the solute particles are too small to scatter light.

Quick check

  1. In a fizzy drink, carbon dioxide gas is dissolved in sweetened water. What is the solvent?1 mark

3. Solubility and Saturated Solutions

Solubility is a measure of how much solute can dissolve in a certain amount of solvent at a specific temperature. It is usually expressed as 'grams of solute per 100 grams of solvent' (g/100g solvent). When you keep adding solute to a solvent, you eventually reach a point where no more can dissolve. At this point, the solution is said to be saturated. Any solution that can still dissolve more solute is called an unsaturated solution. If you add more solute to a saturated solution, it will simply sink to the bottom without dissolving.

Solubility (g per 100g solvent) = (mass of solute / mass of solvent) × 100

Key term

Saturated Solution: A solution in which the maximum amount of solute has been dissolved in a solvent at a particular temperature.

Common pitfall

Forgetting to state the temperature when quoting a solubility value, as solubility is highly dependent on temperature.

Worked example 12 marks

A student finds that a maximum of 9g of a salt dissolves in 25g of water at 20°C. Calculate the solubility of the salt in g per 100g of water at this temperature.

  1. 1

    The ratio of solute to solvent is 9g of salt to 25g of water.

  2. 2

    To find the solubility per 100g of water, we need to scale this ratio up. The scaling factor is 100g / 25g = 4.

  3. 3

    Multiply the mass of the salt by the scaling factor: 9g × 4 = 36g.

  4. 4

    The solubility is 36g per 100g of water.

Worked example 23 marks

The solubility of potassium chloride at 40°C is 40 g/100 g water. Is a solution containing 10g of potassium chloride in 50g of water at 40°C saturated?

  1. 1

    First, calculate how much potassium chloride can dissolve in 50g of water at 40°C.

  2. 2

    If 40g dissolves in 100g of water, then half that amount (40g / 2 = 20g) will dissolve in 50g of water.

  3. 3

    The solution contains only 10g of potassium chloride, which is less than the maximum of 20g that could dissolve.

  4. 4

    Therefore, the solution is unsaturated.

Recap

  • Solubility measures the maximum mass of solute that can dissolve in a fixed mass of solvent.
  • A saturated solution holds the maximum possible amount of dissolved solute at that temperature.
  • An unsaturated solution can dissolve more solute.
  • Solubility is always quoted at a specific temperature.

Quick check

  1. If the solubility of a substance is 30g per 100g of water, is a solution containing 35g of the substance in 100g of water saturated or unsaturated? What would you observe?2 marks

4. Factors Affecting Solubility and Rate of Dissolving

Several factors can change how much or how fast a substance dissolves. It's crucial to distinguish between factors affecting solubility (how much dissolves) and the rate of dissolving (how fast it dissolves). For most solid solutes, solubility increases as the temperature of the solvent increases. For gases, the opposite is true: their solubility decreases as temperature increases. The rate of dissolving is increased by: 1) Higher temperature (particles have more energy and move faster), 2) Stirring (brings fresh solvent into contact with the solute), and 3) Increased surface area (e.g., powder dissolves faster than a large crystal).

Key term

Solubility Curve: A graph showing how the solubility of a substance in a solvent changes with temperature.

Examiner insight

Examiners reward clear distinctions between 'solubility' (the maximum amount that can dissolve) and the 'rate of dissolving' (how fast it dissolves). Use these terms precisely in your answers.

Worked example 12 marks

A solubility curve shows that the solubility of potassium nitrate at 70°C is 138g/100g water, and at 30°C it is 46g/100g water. If a saturated solution in 100g of water is cooled from 70°C to 30°C, what mass of potassium nitrate will crystallise out?

  1. 1

    Mass of solute dissolved at 70°C = 138g.

  2. 2

    Mass of solute dissolved at 30°C = 46g.

  3. 3

    The difference between these two values is the mass of solid that can no longer stay dissolved as the solution cools.

  4. 4

    Mass crystallised = Mass at 70°C - Mass at 30°C = 138g - 46g = 92g.

Recap

  • The solubility of most solids increases as temperature increases.
  • The solubility of all gases decreases as temperature increases.
  • The rate of dissolving is increased by higher temperature, stirring, and greater surface area.
  • A solubility curve graphically represents the effect of temperature on solubility.
  • Cooling a saturated solution often causes the solute to crystallise.

Quick check

  1. Why does sugar dissolve faster in hot tea than in iced tea?1 mark
  2. Why does a can of soda go flat faster when it is left open at room temperature compared to in the fridge?2 marks

5. Separating Mixtures: Paper Chromatography

Paper chromatography is a technique used to separate and identify substances in a mixture, such as the different coloured dyes in an ink. It works because different substances have different solubilities in the solvent and different levels of attraction to the paper. In the experiment, a spot of the mixture is placed on a pencil line on chromatography paper (the stationary phase). The paper is then dipped into a solvent (the mobile phase), which soaks up the paper. As the solvent moves past the spot, it dissolves the mixture and carries it up the paper. Substances that are more soluble in the solvent and less attracted to the paper travel further, separating the mixture into its components.

Rf = (distance travelled by substance) / (distance travelled by solvent front)

Key term

Rf value (Retardation factor): A ratio used in chromatography to identify a substance, calculated by dividing the distance the spot travelled by the distance the solvent front travelled.

Common pitfall

Drawing the baseline in pen instead of pencil. The ink from the pen would dissolve in the solvent and interfere with the chromatogram, making the results invalid.

Worked example 12 marks

In a chromatogram, the solvent front moved 9.0 cm up the paper from the baseline. A blue spot from a food colouring moved 3.6 cm. Calculate the Rf value for the blue spot.

  1. 1

    State the formula: Rf = distance travelled by substance / distance travelled by solvent front.

  2. 2

    Substitute the values for the blue spot: Rf = 3.6 cm / 9.0 cm.

  3. 3

    Calculate the result: Rf = 0.4.

  4. 4

    The Rf value has no units as it is a ratio.

Recap

  • Chromatography separates mixtures based on differences in solubility and attraction to the paper.
  • The stationary phase is the paper and the mobile phase is the solvent.
  • The starting line must be drawn in pencil so it does not dissolve and run.
  • The Rf value is always less than 1.
  • A pure substance will produce only one spot in a chromatogram.

Quick check

  1. An unknown substance is analysed using chromatography and produces two different spots. Is the substance a pure compound or a mixture?1 mark

6. Filtration, Evaporation, and Distillation

These are common laboratory techniques used to separate mixtures based on differences in their physical properties. Filtration: Used to separate an insoluble solid from a liquid (e.g., sand from water). The mixture is poured through filter paper in a funnel. The liquid (filtrate) passes through the tiny pores in the paper, while the solid (residue) is trapped. Evaporation: Used to separate a soluble solid (solute) from a liquid (solvent) when you want to keep the solid. The solution is heated, causing the solvent to turn into a gas and escape, leaving the solid crystals behind. Simple Distillation: Used to separate a liquid solvent from a solution when you want to keep the liquid. The solution is heated to its boiling point, the solvent vaporises, passes into a condenser where it is cooled, and turns back into a pure liquid (distillate) which is collected separately.

Key term

Filtrate: The liquid that has passed through a filter during the process of filtration.

Examiner insight

For questions asking you to describe a separation, be specific about the apparatus (e.g., filter funnel and paper, evaporating basin, condenser) and the state of the substances at each stage.

Worked example 14 marks

Describe how you would obtain a sample of pure water from a solution of salt water.

  1. 1

    The method to use is simple distillation.

  2. 2

    Pour the salt water into a distillation flask and heat it gently.

  3. 3

    The water will boil at 100°C, turn into steam, and leave the salt behind in the flask.

  4. 4

    The steam will travel into a Liebig condenser, which has cold water flowing through its outer jacket.

  5. 5

    The condenser will cool the steam, causing it to condense back into pure liquid water.

  6. 6

    This pure water (the distillate) is collected in a beaker at the end of the condenser.

Recap

  • Filtration separates an insoluble solid from a liquid.
  • Evaporation separates a dissolved solid from a solution.
  • Simple distillation separates a liquid solvent from a solution.
  • The choice of separation technique depends on the physical properties of the substances in the mixture.
  • Fractional distillation is used to separate a mixture of liquids with different boiling points.

Quick check

  1. Which technique would you use to separate sand from a mixture of sand and water?1 mark
  2. Which technique would you use to get solid salt from a salt water solution?1 mark

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. Define the terms 'solute' and 'solvent', giving an example for each.2 marks
  2. Classify helium (He), bronze (an alloy of copper and tin), and sugar (C₁₂H₂₂O₁₁) as an element, compound, or mixture. Justify your answers.3 marks
  3. A student wants to find out how the temperature of water affects the time it takes for a sugar cube to dissolve. Describe the key steps of a fair investigation they could carry out.4 marks
  4. In a chromatography experiment, a spot of green ink separates into a yellow spot and a blue spot. The solvent front travelled 10.0 cm. The yellow spot travelled 8.0 cm and the blue spot travelled 4.0 cm. Calculate the Rf values for both spots.3 marks
  5. Explain, using the idea of particles, what happens when salt dissolves in water.3 marks
  6. You are given a mixture of iron filings (which are magnetic), sand (insoluble), and salt (soluble). Describe a method to separate this mixture to obtain a dry sample of each component.6 marks
  7. The solubility of substance X in water is 40 g/100 g at 20°C and 65 g/100 g at 50°C. A solution is made by dissolving 50 g of X in 100 g of water at 50°C. Is this solution saturated or unsaturated? The solution is then cooled to 20°C. What will you observe? Explain your answer, stating the mass of any solid formed.4 marks
  8. Which single separation technique is most suitable for obtaining pure water from sea water?1 mark
  9. Explain the difference between a saturated and an unsaturated solution at a molecular level.2 marks
  10. A student claims that a sample of black ink is a pure substance. Describe a simple experiment you could perform to test this claim and explain the possible results.4 marks

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