Cambridge Lower Secondary CheckpointStage 8

Physics: Light and sound

Science Stage 8 Chapter Notes

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Physics: Light and sound
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1. Fundamentals of Waves

Both light and sound are forms of energy that travel as waves. A wave is a disturbance that transfers energy from one place to another without transferring matter. There are two main types of waves. Transverse waves, like light, have oscillations (vibrations) that are perpendicular (at 90°) to the direction of energy transfer. Longitudinal waves, like sound, have oscillations that are parallel to the direction of energy transfer, consisting of compressions and rarefactions. Key properties include: Amplitude (the maximum displacement from the equilibrium position), Wavelength (λ, the distance between two consecutive identical points on a wave), Frequency (f, the number of complete waves passing a point per second, measured in Hertz), and Period (T, the time taken for one complete wave to pass a point). The speed of a wave(v) is related to its frequency and wavelength by the wave speed equation: v = fλ.

v = fλ (Wave speed = frequency × wavelength)

f = 1/T (Frequency = 1 / Period)

Key term

Transverse Wave: A wave in which the particles of the medium vibrate at right angles (perpendicular) to the direction of energy transfer.

Common pitfall

Confusing the movement of the wave itself with the movement of the particles in the medium. The particles oscillate about a fixed point, while the wave propagates forward.

Fun fact

If you do 'the wave' in a stadium, you are creating a transverse wave. The people (particles) move up and down, but the wave (energy) travels around the stadium.

Worked example 13 marks

A red light wave has a frequency of 4.6 x 10¹⁴ Hz and a wavelength of 6.5 x 10⁻⁷ m. Calculate the speed of the light wave.

  1. 1

    Step 1: State the formula relating wave speed, frequency, and wavelength. v = fλ

  2. 2

    Step 2: Substitute the given values into the formula. v = (4.6 x 10¹⁴ Hz) × (6.5 x 10⁻⁷ m)

  3. 3

    Step 3: Calculate the result. v = 29.9 x 10⁷ m/s, which is approximately 3.0 x 10⁸ m/s.

  4. 4

    Answer: The speed of the light wave is 3.0 x 10⁸ m/s.

Recap

  • Waves transfer energy, not matter.
  • Light is a transverse wave; its vibrations are perpendicular to the direction of travel.
  • Sound is a longitudinal wave; its vibrations are parallel to the direction of travel.
  • Wave speed is calculated by multiplying frequency and wavelength (v = fλ).
  • Frequency is the number of waves per second, measured in Hertz (Hz).

Quick check

  1. What is the key difference between a transverse and a longitudinal wave?2 marks
  2. A wave has a frequency of 10 Hz. What is its period?1 mark

2. Reflection of Light

Reflection occurs when light bounces off a surface. A smooth, shiny surface like a plane mirror reflects light in a predictable way. To describe this, we imagine a line drawn at 90° to the surface at the point where the light hits; this line is called the normal. The incoming ray of light is the incident ray, and the outgoing ray is the reflected ray. The Law of Reflection states that the angle of incidence (the angle between the incident ray and the normal) is equal to the angle of reflection (the angle between the reflected ray and the normal). An image formed by a plane mirror is virtual (it cannot be projected onto a screen), upright, laterally inverted (left and right are swapped), the same size as the object, and appears to be as far behind the mirror as the object is in front of it.

Angle of incidence (i) = Angle of reflection (r)

Key term

Law of Reflection: The principle stating that the angle of incidence is equal to the angle of reflection, and the incident ray, reflected ray, and normal all lie in the same plane.

Examiner insight

Examiners award marks for accurately drawn ray diagrams that include arrows on the rays and a clearly labelled normal drawn perpendicular to the surface.

Common pitfall

Measuring the angles of incidence and reflection from the mirror surface instead of from the normal.

Worked example 13 marks

A ray of light strikes a plane mirror. The angle between the incident ray and the mirror surface is 30°. Draw a ray diagram and determine the angle of reflection.

  1. 1

    Step 1: Draw the plane mirror surface and the incident ray hitting it at an angle of 30° to the surface.

  2. 2

    Step 2: At the point of incidence, draw the normal, which is a dashed line perpendicular (at 90°) to the mirror surface.

  3. 3

    Step 3: Calculate the angle of incidence (i). This is the angle between the incident ray and the normal. i = 90° - 30° = 60°.

  4. 4

    Step 4: Apply the Law of Reflection (i = r). The angle of reflection(r) must also be 60°.

  5. 5

    Step 5: Draw the reflected ray such that the angle between it and the normal is 60°. Add arrows to both rays to show the direction of light.

  6. 6

    Answer: The angle of reflection is 60°.

Recap

  • The Law of Reflection states that the angle of incidence equals the angle of reflection.
  • Angles of incidence and reflection are always measured from the normal, not the surface.
  • The normal is an imaginary line drawn at 90° to the reflecting surface.
  • Images in a plane mirror are virtual, upright, and laterally inverted.

Quick check

  1. List three characteristics of an image formed in a plane mirror.3 marks

3. Refraction of Light

Refraction is the bending of light as it passes from one medium to another, for example, from air into glass. This happens because light travels at different speeds in different materials. It travels fastest in a vacuum, slightly slower in air, and slower still in denser materials like water or glass. When light enters a denser medium at an angle, it slows down and bends towards the normal. When it enters a less dense medium, it speeds up and bends away from the normal. The amount of bending is related to the material's refractive index (n), a measure of how much it slows down light. A higher refractive index means more bending.

n = sin(i) / sin(r)

n = speed of light in vacuum (c) / speed of light in medium (v)

Key term

Refraction: The change in direction of a wave passing from one medium to another, caused by its change in speed.

Examiner insight

When drawing refraction diagrams, ensure the ray of light is shown as a single straight line within the medium, only bending at the boundaries.

Common pitfall

Confusing the conditions for bending towards the normal versus away from the normal. Remember 'FST' (Faster, Slower, Towards) and 'SFA' (Slower, Faster, Away).

Fun fact

The 'bent' appearance of a straw in a glass of water is a classic everyday example of refraction.

Worked example 13 marks

A ray of light passes from air into a block of glass. The angle of incidence is 45° and the angle of refraction is 28°. Calculate the refractive index of the glass.

  1. 1

    Step 1: State the formula for refractive index (Snell's Law): n = sin(i) / sin(r).

  2. 2

    Step 2: Identify the given values: angle of incidence(i) = 45°, angle of refraction(r) = 28°.

  3. 3

    Step 3: Substitute the values into the formula: n = sin(45°) / sin(28°).

  4. 4

    Step 4: Calculate the values of sin: sin(45°) ≈ 0.707, sin(28°) ≈ 0.470.

  5. 5

    Step 5: Perform the division: n = 0.707 / 0.470 ≈ 1.50.

  6. 6

    Answer: The refractive index of the glass is 1.50.

Recap

  • Refraction is the bending of light due to a change in speed when it crosses the boundary between two media.
  • Light bends towards the normal when entering a denser medium (slowing down).
  • Light bends away from the normal when entering a less dense medium (speeding up).
  • Refractive index (n) is a ratio that quantifies how much a material bends light.

Quick check

  1. What happens to the speed and direction of a light ray as it enters a glass block from air at an angle?2 marks

4. Total Internal Reflection

When light travels from a denser medium to a less dense medium (e.g., from glass to air), it bends away from the normal. If you increase the angle of incidence, the angle of refraction gets bigger, until it reaches 90°. The angle of incidence that causes this is called the critical angle (c). If the angle of incidence is increased beyond the critical angle, the light no longer refracts out of the medium. Instead, it is completely reflected back into the denser medium. This phenomenon is called Total Internal Reflection (TIR). Two conditions must be met for TIR: 1. The light must be travelling from a denser medium to a less dense one. 2. The angle of incidence must be greater than the critical angle. This principle is vital for technologies like optical fibres used in broadband internet and keyhole surgery.

sin(c) = 1 / n (where c is the critical angle and n is the refractive index of the denser medium)

Key term

Critical Angle (c): The angle of incidence in a denser medium for which the angle of refraction in the less dense medium is 90 degrees.

Examiner insight

Clearly stating both necessary conditions for TIR is often worth full marks on descriptive questions. Don't just say the angle is 'large'; you must state it is 'greater than the critical angle'.

Common pitfall

Forgetting that TIR can only happen when light is trying to exit a denser medium, not when it is entering one.

Worked example 13 marks

The refractive index of a type of glass is 1.52. Calculate its critical angle.

  1. 1

    Step 1: State the formula relating the critical angle and refractive index: sin(c) = 1 / n.

  2. 2

    Step 2: Substitute the given refractive index: sin(c) = 1 / 1.52.

  3. 3

    Step 3: Calculate the value of the fraction: sin(c) ≈ 0.658.

  4. 4

    Step 4: Find the angle by taking the inverse sine (arcsin or sin⁻¹): c = sin⁻¹(0.658).

  5. 5

    Step 5: Calculate the final answer: c ≈ 41.1°.

  6. 6

    Answer: The critical angle for this glass is 41.1°.

Worked example 24 marks

Explain, with the aid of a simple diagram, how an optical fibre transmits light.

  1. 1

    Step 1: Draw a long, thin fibre. Show a ray of light entering one end at an angle.

  2. 2

    Step 2: Inside the fibre, show the ray of light striking the internal boundary at a large angle (greater than the critical angle).

  3. 3

    Step 3: Show the ray undergoing total internal reflection and bouncing off the internal surface, continuing along the fibre.

  4. 4

    Step 4: Explain that the optical fibre is made of a very pure, dense glass or plastic core. Light travelling down it always strikes the internal boundary at an angle greater than the critical angle.

  5. 5

    Step 5: Conclude that this causes repeated total internal reflections, trapping the light inside and guiding it along the fibre, even around corners, with very little energy loss.

Recap

  • Total Internal Reflection (TIR) occurs when light is completely reflected back into a denser medium.
  • Two conditions for TIR: moving from denser to less dense medium, and angle of incidence > critical angle.
  • The critical angle is the angle of incidence that produces a 90° angle of refraction.
  • Optical fibres use TIR to transmit data as pulses of light over long distances.

Quick check

  1. What are the two conditions required for total internal reflection?2 marks

5. Lenses and Image Formation

Lenses are curved pieces of glass or plastic designed to refract light in a predictable way. A converging (or convex) lens is thicker in the middle and causes parallel rays of light to converge at a single point called the principal focus or focal point. A diverging (or concave) lens is thinner in the middle and causes parallel rays to spread out as if they came from a focal point. The distance from the centre of the lens to the focal point is the focal length. By drawing 'ray diagrams' using a few key rules, we can predict the location, size, and nature of the image formed by a lens. Images can be real (can be projected onto a screen, like in a cinema) or virtual (cannot be projected, like the magnified image in a magnifying glass).

Magnification = Image Height / Object Height

Key term

Focal Length (f): The distance from the centre of the lens to the principal focus (the point where parallel rays of light converge or appear to diverge from).

Common pitfall

Confusing the ray paths for converging and diverging lenses, or incorrectly identifying an image as real when it is virtual (and vice versa).

Fun fact

The lens in the human eye is a converging lens that focuses a real, inverted image onto the retina at the back of the eye. Your brain then flips the image so you see the world the right way up!

Worked example 14 marks

An object 2 cm tall is placed 30 cm from a converging lens with a focal length of 10 cm. Draw a ray diagram to find the position, size and nature of the image.

  1. 1

    Step 1: Draw the principal axis, the lens, and mark the focal points (F) on both sides, 10 cm from the lens centre. Mark the object as an upright arrow 30 cm from the lens.

  2. 2

    Step 2: Draw Ray 1: From the top of the object, draw a ray parallel to the principal axis. After passing through the lens, this ray refracts through the focal point on the other side.

  3. 3

    Step 3: Draw Ray 2: From the top of the object, draw a ray that passes straight through the centre of the lens without changing direction.

  4. 4

    Step 4: The point where these two refracted rays cross is the top of the image. Draw the image as an arrow from the principal axis to this point.

  5. 5

    Step 5: Describe the image. It is located between F and 2F on the other side. It is inverted (upside down), diminished (smaller than the object), and real (formed by the intersection of actual light rays).

Recap

  • Converging (convex) lenses are thicker in the middle and focus parallel light rays.
  • Diverging (concave) lenses are thinner in the middle and spread out parallel light rays.
  • A real image is formed where light rays actually meet and can be projected onto a screen.
  • A virtual image is formed where light rays appear to come from and cannot be projected.
  • Converging lenses are used in cameras and projectors; diverging lenses are used to correct short-sightedness.

Quick check

  1. What type of lens is used as a magnifying glass, and what type of image does it produce in this case?2 marks

6. The Nature of Sound

Sound is a mechanical wave, which means it needs a medium (a substance) to travel through. It cannot travel through a vacuum. Sound is produced by vibrations. These vibrations cause particles of the medium to vibrate back and forth, passing the energy along. In air, this creates a series of compressions (areas where particles are bunched together) and rarefactions (areas where particles are spread apart). Since the particle vibrations are parallel to the direction of energy transfer, sound is a longitudinal wave. The characteristics of a sound are related to the properties of its wave. The pitch of a sound is determined by its frequency; a high frequency gives a high pitch. The loudness (or volume) of a sound is determined by its amplitude; a large amplitude gives a loud sound. Sound travels at different speeds in different media: fastest in solids, slower in liquids, and slowest in gases.

Key term

Longitudinal Wave: A wave in which the particles of the medium vibrate parallel to the direction of energy transfer.

Examiner insight

Students who can clearly link the physical properties of a sound wave (frequency, amplitude) to the perceived characteristics (pitch, loudness) score highly.

Common pitfall

Mixing up pitch and loudness. Remember: Pitch = Frequency, Loudness = Amplitude.

Fun fact

Whales can communicate using very low-frequency sounds (infrasound) that can travel for hundreds of miles through the ocean.

Worked example 14 marks

The diagram shows two sound waves, A and B, displayed on an oscilloscope. Compare the two sounds in terms of their loudness and pitch.

  1. 1

    Step 1: To compare loudness, compare the amplitudes (the height of the waves from the centre line). Wave A has a larger amplitude than wave B.

  2. 2

    Step 2: Relate amplitude to loudness. A larger amplitude means a louder sound. Therefore, sound A is louder than sound B.

  3. 3

    Step 3: To compare pitch, compare the frequencies (how many waves are shown in the same time period). Waves A and B have the same number of waves in the same horizontal distance.

  4. 4

    Step 4: Relate frequency to pitch. The same frequency means the same pitch. Therefore, sounds A and B have the same pitch.

  5. 5

    Answer: Sound A is louder than sound B, but they have the same pitch.

Recap

  • Sound is a longitudinal wave that requires a medium to travel.
  • Sound travels as a series of compressions and rarefactions.
  • Pitch is determined by the frequency of the sound wave.
  • Loudness is determined by the amplitude of the sound wave.
  • Sound travels fastest through solids, then liquids, then gases.

Quick check

  1. Why can't an astronaut on a spacewalk hear an explosion happening nearby?1 mark
  2. How would the wave for a quiet, high-pitched sound look on an oscilloscope screen?2 marks

7. Echoes and the Speed of Sound

An echo is a reflection of a sound wave. When a sound wave hits a hard, flat surface like a cliff face or a wall, it bounces back. If the surface is far enough away, you will hear the reflected sound as a distinct echo after you hear the original sound. This principle is used in technologies like SONAR (Sound Navigation and Ranging) to map the seabed or locate submarines. We can use echoes to measure the speed of sound. The relationship is the familiar `speed = distance / time`. However, for an echo, the sound travels to the reflector and back again, so the total distance travelled is twice the distance to the reflector. The formula becomes `Speed of sound = (2 × Distance to reflector) / time taken for echo`.

Speed = Total Distance / Time

Total Distance for an echo = 2 × distance to reflector

Key term

Echo: A reflection of a sound wave that arrives at the listener with a delay after the direct sound.

Examiner insight

Show your working clearly in echo calculations, explicitly stating the formula and the total distance travelled to ensure you get marks even if your final calculation is incorrect.

Common pitfall

Forgetting to double the distance (or halve the time) in echo calculations. The time given is for the sound's entire round trip.

Fun fact

Bats and dolphins use a biological version of sonar called echolocation to navigate and find prey in the dark or in murky water.

Worked example 13 marks

A person stands 255 metres from a tall cliff and claps their hands. They hear the echo 1.5 seconds later. Calculate the speed of sound in air.

  1. 1

    Step 1: Identify the distance to the reflector(d) and the time for the echo (t). d = 255 m, t = 1.5 s.

  2. 2

    Step 2: Calculate the total distance the sound travelled. The sound goes to the cliff and back. Total distance = 2 × d = 2 × 255 m = 510 m.

  3. 3

    Step 3: State the formula for speed: speed = total distance / time.

  4. 4

    Step 4: Substitute the values and calculate: speed = 510 m / 1.5 s.

  5. 5

    Step 5: speed = 340 m/s.

  6. 6

    Answer: The speed of sound is 340 m/s.

Recap

  • An echo is a sound wave that has been reflected from a surface.
  • The time it takes to hear an echo can be used to calculate distance or speed.
  • In echo calculations, the total distance travelled by the sound is twice the distance to the reflecting surface.
  • The formula is `speed = (2 × distance) / time`.

Quick check

  1. A ship's sonar sends a pulse of sound to the seabed. The echo returns in 0.6 s. The speed of sound in seawater is 1500 m/s. How deep is the sea?3 marks

End-of-chapter exercise

Test yourself on the whole chapter. Work through these before moving on.

  1. State the law of reflection and draw a simple ray diagram to illustrate it, labelling the incident ray, reflected ray, normal, angle of incidence, and angle of reflection.4 marks
  2. A sound wave in air has a frequency of 250 Hz and a wavelength of 1.36 m. Calculate the speed of the sound wave. If this sound wave enters water, what property of the wave (speed, frequency, or wavelength) remains constant?4 marks
  3. A ship uses an ultrasound scanner to measure the depth of the sea. A pulse of ultrasound is sent from the ship, and the reflected pulse is detected 0.6 seconds later. If the speed of sound in seawater is 1500 m/s, calculate the depth of the sea.3 marks
  4. Explain, with the aid of a diagram, why a straw in a glass of water appears to be bent at the water's surface.4 marks
  5. Describe the difference between a longitudinal wave and a transverse wave. Give one example of each.3 marks
  6. A ray of light travelling in air strikes the surface of a diamond (refractive index = 2.42) at an angle of incidence of 60°. Calculate the angle of refraction inside the diamond.3 marks
  7. Draw a ray diagram to show how a converging lens can be used as a magnifying glass to produce a virtual, upright, and magnified image. Label the object, image, and one focal point.4 marks
  8. Explain the two conditions that are necessary for total internal reflection to occur. Give one example of a technology that uses this principle.3 marks
  9. A guitar string is plucked gently, and then plucked much harder. Describe the difference you would expect in the sound produced in terms of loudness and pitch. Explain your answer with reference to the properties of the sound wave.4 marks
  10. A student stands exactly halfway between two large parallel cliffs. She claps her hands once and hears the first echo after 1.2 seconds. Calculate the distance between the two cliffs. (Speed of sound in air = 340 m/s).4 marks

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